The first-order rate constant for the decomposition of NjOs, given below, at 70°C is 6.82 x 10s. Suppose we start with 0.0150 mol of N₂O(g) in a volume of 1.0 L 2 N₂O5(0)4 NO₂(g) + O₂(g) (a) How many moles of N,O, will remain after 3.0 min? 0.004 X mol (b) How many minutes will it take for the quantity of No, to drop to 0.005 mol? 2.68 ✔min (c) What is the half-life of N.O, at 70 C7 101.0 x min

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The first-order rate constant for the decomposition of Njos, given below, at 70°C is 6.82 x 10 s¹. Suppose we start with 0.0150 mol of NO(g) in a volume of 1.0L
2 N₂0 (0) 4 NO₂(g) + O₂(g)
(a) How many moles of N,O, will remain after 3.0 min?
0.004
X mol
(b) How many minutes will it take for the quantity of N₂0, to drop to 0.005 mol?
12.68
✓min
(c) What is the half-life of N,O, at 20°C
101.0
x min
Transcribed Image Text:The first-order rate constant for the decomposition of Njos, given below, at 70°C is 6.82 x 10 s¹. Suppose we start with 0.0150 mol of NO(g) in a volume of 1.0L 2 N₂0 (0) 4 NO₂(g) + O₂(g) (a) How many moles of N,O, will remain after 3.0 min? 0.004 X mol (b) How many minutes will it take for the quantity of N₂0, to drop to 0.005 mol? 12.68 ✓min (c) What is the half-life of N,O, at 20°C 101.0 x min
Molecular iodine, 1₂(g), dissociates into iodine atoms at 625 K with a first-order rate constant of 0.271 s
(a) What is the half-life for this reaction?
2.56
(b) If you start with 0.046 M 1₂ at this temperature, how much will remain after 5.17 s assuming that the iodine atoms do not recombine to form 1,?
0.011
XM D
Transcribed Image Text:Molecular iodine, 1₂(g), dissociates into iodine atoms at 625 K with a first-order rate constant of 0.271 s (a) What is the half-life for this reaction? 2.56 (b) If you start with 0.046 M 1₂ at this temperature, how much will remain after 5.17 s assuming that the iodine atoms do not recombine to form 1,? 0.011 XM D
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