The figure shows a small lightbulb suspended at distance di = 330 cm above the surface of the water in a swimming pool where the water depth is d2 = 290 cm. The bottom of the pool is a large mirror. How far below the mirror surface is the image of the bulb? (Hint: Construct a diagram of two rays like that of figure (b) below, but take into account the bending of light rays by refraction at the water surface. Assume that the indices of refraction of the air and the water are 1.00 and 1.33 respectively, and the rays are close to a vertical axis through the bulb, and use the small-angle approximation in which sin 0 x tan 0 x 0.) de Mirror em Mirror lem (a) (b) plem blem Number Units oblem the tolerance is +/-5%
The figure shows a small lightbulb suspended at distance di = 330 cm above the surface of the water in a swimming pool where the water depth is d2 = 290 cm. The bottom of the pool is a large mirror. How far below the mirror surface is the image of the bulb? (Hint: Construct a diagram of two rays like that of figure (b) below, but take into account the bending of light rays by refraction at the water surface. Assume that the indices of refraction of the air and the water are 1.00 and 1.33 respectively, and the rays are close to a vertical axis through the bulb, and use the small-angle approximation in which sin 0 x tan 0 x 0.) de Mirror em Mirror lem (a) (b) plem blem Number Units oblem the tolerance is +/-5%
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Transcribed Image Text:The figure shows a small lightbulb suspended at distance di = 330 cm above the surface of the water in a swimming pool where the water depth is d2 = 290 cm. The
bottom of the pool is a large mirror. How far below the mirror surface is the image of the bulb? (Hint: Construct a diagram of two rays like that of figure (b) below, but
take into account the bending of light rays by refraction at the water surface. Assume that the indices of refraction of the air and the water are 1.00 and 1.33
respectively, and the rays are close to a vertical axis through the bulb, and use the small-angle approximation in which sin 0 x tan 0 x 0.)
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Mirror
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Number
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the tolerance is +/-5%
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