The figure below shows a right triangular prism, with angles as shown, made of zircon immersed in water. The base of the prism is horizontal. A horizontal light ray is incident and normal to the left vertical face of the prism. It undergoes total internal reflection at point P and exits the prism at the bottom with a refraction angle of 0,. The index of refraction of zircon is 1.923. 60.0° n2 30.0% (a) What is the exit angle 0, (in degrees)? 39.35 If the light ray is reflected at P, what is the reflection angle? Use this and the geometry of triangles to determine 0,, then

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The figure below shows a right triangular prism, with angles as shown, made of zircon immersed in water. The base of the prism is
horizontal. A horizontal light ray is incident and normal to the left vertical face of the prism. It undergoes total internal reflection
at point P and exits the prism at the bottom with a refraction angle of 02. The index of refraction of zircon is 1.923.
60.0°
n2
30.0°%
(a) What is the exit angle 03 (in degrees)?
39.35
If the light ray is reflected at P, what is the reflection angle? Use this and the geometry of triangles to determine 0,, then
use Snell's law to find 02. °
Transcribed Image Text:The figure below shows a right triangular prism, with angles as shown, made of zircon immersed in water. The base of the prism is horizontal. A horizontal light ray is incident and normal to the left vertical face of the prism. It undergoes total internal reflection at point P and exits the prism at the bottom with a refraction angle of 02. The index of refraction of zircon is 1.923. 60.0° n2 30.0°% (a) What is the exit angle 03 (in degrees)? 39.35 If the light ray is reflected at P, what is the reflection angle? Use this and the geometry of triangles to determine 0,, then use Snell's law to find 02. °
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