Incoming ray Outgoing ray 90° – 0 Mirror base
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A light ray traveling in air is incident on one face of a right-angle prism with index of refraction n = 1.49, as shown in Figure P22.54, and the ray follows the path shown in the figure. Assuming that θ = 58.0° and the base of the prism is mirrored, determine the angle made by the outgoing ray with the normal to the right face of the prism.
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- Air has an index of refraction of 1.00. Water has an index of refraction of 1.33. Consider a pool of water that is perfectly calm and 3.21 meters deep. A ray of light (or a laser beam, if you like) enters the water, refracts, and ultimately hits the bottom of the pool. Find the distance between the point where the light enters the water and the point where the light hits the bottom of the pool if the angle between the ray in air and the surface of the pool is 46.4 degrees. Answer in meters.A ray of light crosses the boundary between some substance with n = 1.54 and air, going from the substance into air. If the angle of incidence is 29◦ what is the angle of refraction? Calculate to 1decimal.take ur time
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