The figure shows a plot of potential energy U versus position x of a 0.260 kg particle that can travel only along an x axis under the influence of a conservative force. The graph has these values: UA = 9.00 J, Uc=20.0 J and Up = 24.0 J. The particle is released at the point where U forms a "potential hill" of "height" Ug = 12.0 J, with kinetic energy 7.50 J. What is the speed of the particle at (a)x= 3.50 m and (b)x= 6.50 m? What is the position of the turning point on (c) the right side and (d) the left side? (a) Number i (b) Number i (c) Number i W 4 5 6 x (m) U(J) Uch UB U₁ 0 lov 2 3 Units Units Units 8 <

The figure shows a plot of potential energy U versus position x of a 0.260 kg particle that can travel only along an x axis under the influence of a conservative force. The graph has these values: UA = 9.00 J, Uc=20.0 J and Up = 24.0 J. The particle is released at the point where U forms a "potential hill" of "height" Ug = 12.0 J, with kinetic energy 7.50 J. What is the speed of the particle at (a)x= 3.50 m and (b)x= 6.50 m? What is the position of the turning point on (c) the right side and (d) the left side? (a) Number i (b) Number i (c) Number i W 4 5 6 x (m) U(J) Uch UB U₁ 0 lov 2 3 Units Units Units 8 <

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Description: The figure shows a plot of potential energy U versus position x of a 0.260 kg particle thatcan travel only along an x axis under the influence of a conservative force. The graph hasthese values: UA = 9.00 J, Uc=20.0 J and Up = 24.0 J. The particle i

College Physics

11th Edition

ISBN:9781305952300

Author:Raymond A. Serway, Chris Vuille

Publisher:Raymond A. Serway, Chris Vuille

Chapter1: Units, Trigonometry. And Vectors

Section: Chapter Questions

Problem 1CQ: Estimate the order of magnitude of the length, in meters, of each of the following; (a) a mouse, (b)...

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The figure here shows a plot of potential energy U versus position x of a 0.898 kg particle that can travel only along an x axis. (Nonconservative forces are not involved.) Three values are UA = 15.0 J, UB = 35.0 J and Uc = 45.0 J. The particle is released at x = 4.50 m with an initial speed of 7.52 m/s, headed in the negative x direction. (a) If the particle can reach x = 1.00 m, what is its speed there, and if it cannot, what is its turning point? What are the (b) magnitude and (c) direction of the force on the particle as it begins to move to the left of x = 4.00 m? Suppose, instead, the particle is headed in the positive x direction when it is released at x = 4.50 m at speed 7.52 m/s. (d) If the particle can reach x = 7.00 m, what is its speed there, and if it cannot, what is its turning point? What are the (e) magnitude and (f) direction of the force on the particle as it begins to move to the right of x = 5.00 m? Uc UB UA 2 4 x (m) (a) Number i Unit (b) Number i Unit (c) (d)…
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The figure here shows a plot of potential energy U versus position x of a 0.878 kg particle that can travel only along an x axis. (Nonconservative forces are not involved.) Three values are UA-15.0J, Us - 35.0 J and Uc-45.0 J. The particle is released at x -4.50 m with an initial speed of 7.99 m/s, headed in the negative x direction. (a) If the particle can reach x -1.00 m, what is its speed there, and if it cannot, what is its turning point? What are the (b) magnitude and (c) direction of the force on the particle as it begins to move to the left of x- 4.00 m? Suppose, instead, the particle is headed in the positive x direction when it is released at x - 4.50 m at speed 7.99 m/s. (d) If the particle can reach x - 7.00 m, what is its speed there, and if it cannot, what is its turning point? What are the (e) magnitude and (f) direction of the force on the particle as it begins to move to the right of x-5.00 m? (0)2 Ucr UB UA 2 (a) Number (b) Number 10 4 x (m) (c) positive (+x) (e)…
The figure here shows a plot of potential energy U versus position x of a 0.877 kg particle that can travel only along an x axis. (Nonconservative forces are not involved.) Three values are UA = 15.0 J, Ug = 35.0 J and Uc = 45.0 J. The particle is released at x = 4.50 m with an initial speed of 7.39 m/s, headed in the negative x direction. (a) If the particle can reach x = 1.00 m, what is its speed there, and if it cannot, what is its turning point? What are the (b) magnitude and (c) direction of the force on the particle as it begins to move to the left of x = 4.00 m? Suppose, instead, the particle is headed in the positive x direction when it is released at x = 4.50 m at speed 7.39 m/s. (d) If the particle can reach x = 7.00 m, what is its speed there, and if it cannot, what is its turning point? What are the (e) magnitude and (f) direction of the force on the particle as it begins to move to the right of x = 5.00 m? Uc UB UA 4. x (m) (a) Number | Unit (b) Number Unit (c) (d) Number…
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