The figure shows a plot of potential energy U versus position x of a 0.250 kg particle that can travel only along an x axis under the influence of a conservative force. The graph has these values: UA-9.00 J, Uc=20.0 J and Up - 24.0 J. The particle is released at the point where U forms a "potential hill" of "height" Ug = 12.0 J. with kinetic energy 5.00 J. What is the speed of the particle at (a)x= 3.50 m and (b)x= 6.50m? What is the position of the turning point on (c) the right side and (d) the left side? UC) Ud U₂ UA

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