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The figure here shows a plot of potential energy U versus position x of a 0.866 kg particle that can travel only along an x axis. (Nonconservative forces are not involved.) Three values are U₁A = 15.0 J, Ug = 35.0 J and Uc= 45.0 J. The particle is released at x = 4.50 m with an initial speed of 7.40 m/s, headed in the negative x direction. (a) If the particle can reach x = 1.00 m, what is its speed there, and if it cannot, what is its turning point? What are the (b) magnitude and (c) direction of the force on the particle as it begins to move to the left of x = 4.00 m? Suppose, instead, the particle is headed in the positive x direction when it is released at x = 4.50 m at

The figure here shows a plot of potential energy U versus position x of a 0.866 kg particle that can travel only along an x axis. (Nonconservative forces are not involved.) Three values are U₁A = 15.0 J, Ug = 35.0 J and Uc= 45.0 J. The particle is released at x = 4.50 m with an initial speed of 7.40 m/s, headed in the negative x direction. (a) If the particle can reach x = 1.00 m, what is its speed there, and if it cannot, what is its turning point? What are the (b) magnitude and (c) direction of the force on the particle as it begins to move to the left of x = 4.00 m? Suppose, instead, the particle is headed in the positive x direction when it is released at x = 4.50 m at

College Physics
College Physics
11th Edition
ISBN:9781305952300
Author:Raymond A. Serway, Chris Vuille
Publisher:Raymond A. Serway, Chris Vuille
Chapter1: Units, Trigonometry. And Vectors
Section: Chapter Questions
Problem 1CQ: Estimate the order of magnitude of the length, in meters, of each of the following; (a) a mouse, (b)...
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The figure shows a plot of potential energy \( U \) versus position \( x \) for a 0.866 kg particle that can travel only along an \( x \)-axis. (Nonconservative forces are not involved.) Three values are \( U_A = 15.0 \, \text{J} \), \( U_B = 35.0 \, \text{J} \), and \( U_C = 45.0 \, \text{J} \). The particle is released at \( x = 4.50 \, \text{m} \) with an initial speed of 7.40 m/s, headed in the negative \( x \) direction. The questions to solve are: (a) If the particle can reach \( x = 1.00 \, \text{m} \), what is its speed there, and if it cannot, what is its turning point? (b) What are the magnitude and (c) direction of the force on the particle as it begins to move to the left of \( x = 4.00 \, \text{m} \)? Suppose, instead, the particle is headed in the positive \( x \) direction when it is released at \( x = 4.50 \, \text{m} \) at 7.40 m/s. (d) If the particle can reach \( x = 7.00 \, \text{m} \), what is its speed there, and if it cannot, what is its turning point? (e) What are the magnitude and (f) direction of the force on the particle as it begins to move to the right of \( x = 5.00 \, \text{m} \)? ### Explanation of the Graph The graph presented is a plot of potential energy \( U \) (in joules, J) along the \( y \)-axis versus position \( x \) (in meters, m) along the \( x \)-axis. - At \( x = 0 \, \text{m} \) to \( x = 2 \, \text{m} \), \( U = U_C = 45.0 \, \text{J} \). - From \( x = 2 \, \text{m} \) to \( x = 4 \, \text{m} \), \(
Transcribed Image Text:The figure shows a plot of potential energy \( U \) versus position \( x \) for a 0.866 kg particle that can travel only along an \( x \)-axis. (Nonconservative forces are not involved.) Three values are \( U_A = 15.0 \, \text{J} \), \( U_B = 35.0 \, \text{J} \), and \( U_C = 45.0 \, \text{J} \). The particle is released at \( x = 4.50 \, \text{m} \) with an initial speed of 7.40 m/s, headed in the negative \( x \) direction. The questions to solve are: (a) If the particle can reach \( x = 1.00 \, \text{m} \), what is its speed there, and if it cannot, what is its turning point? (b) What are the magnitude and (c) direction of the force on the particle as it begins to move to the left of \( x = 4.00 \, \text{m} \)? Suppose, instead, the particle is headed in the positive \( x \) direction when it is released at \( x = 4.50 \, \text{m} \) at 7.40 m/s. (d) If the particle can reach \( x = 7.00 \, \text{m} \), what is its speed there, and if it cannot, what is its turning point? (e) What are the magnitude and (f) direction of the force on the particle as it begins to move to the right of \( x = 5.00 \, \text{m} \)? ### Explanation of the Graph The graph presented is a plot of potential energy \( U \) (in joules, J) along the \( y \)-axis versus position \( x \) (in meters, m) along the \( x \)-axis. - At \( x = 0 \, \text{m} \) to \( x = 2 \, \text{m} \), \( U = U_C = 45.0 \, \text{J} \). - From \( x = 2 \, \text{m} \) to \( x = 4 \, \text{m} \), \(
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