The figure here shows a plot of potential energy U versus position x of a 0.876 kg particle that can travel only along an x axis. (Nonconservative forces are not involved.) Three values are UA = 15.0 J, UB = 35.0 J and Uc = 45.0 J. The particle is released at x = 4.50 m with an initial speed of 7.96 m/s, headed in the negative x direction. (a) If the particle can reach x = 1.00 m, what is its speed there, and if it cannot, what is its turning point? What are the (b) magnitude and (c) direction of the force on the particle as it begins to move to the left of x = 4.00 m? Suppose, instead, the particle is headed in the positive x direction when it is released at x = 4.50 m at speed 7.96 m/s. (d) If the particle can reach x = 7.00 m, what is its speed there, and if it cannot, what is its turning point? What are the (e) magnitude and (f) direction of the force on the particle as it begins to move to the right of x = 5.00 m? UcT UB UA 2 4 6. x (m) ()n

College Physics
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Chapter1: Units, Trigonometry. And Vectors
Section: Chapter Questions
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The figure here shows a plot of potential energy U versus position x of a 0.876 kg
particle that can travel only along an x axis. (Nonconservative forces are not involved.)
Three values are UA = 15.0 J, UB = 35.0 J and Uc = 45.0 J. The particle is released at
x = 4.50 m with an initial speed of 7.96 m/s, headed in the negative x direction. (a) If
the particle can reach x = 1.00 m, what is its speed there, and if it cannot, what is its
turning point? What are the (b) magnitude and (c) direction of the force on the particle
as it begins to move to the left of x = 4.00 m? Suppose, instead, the particle is headed in
the positive x direction when it is released at x = 4.50 m at speed 7.96 m/s. (d) If the
particle can reach x = 7.00 m, what is its speed there, and if it cannot, what is its
turning point? VWhat are the (e) magnitude and (f) direction of the force on the particle
as it begins to move to the right of x = 5.00 m?
Ucr
UB
UA
4.
6
x (m)
2.
Transcribed Image Text:The figure here shows a plot of potential energy U versus position x of a 0.876 kg particle that can travel only along an x axis. (Nonconservative forces are not involved.) Three values are UA = 15.0 J, UB = 35.0 J and Uc = 45.0 J. The particle is released at x = 4.50 m with an initial speed of 7.96 m/s, headed in the negative x direction. (a) If the particle can reach x = 1.00 m, what is its speed there, and if it cannot, what is its turning point? What are the (b) magnitude and (c) direction of the force on the particle as it begins to move to the left of x = 4.00 m? Suppose, instead, the particle is headed in the positive x direction when it is released at x = 4.50 m at speed 7.96 m/s. (d) If the particle can reach x = 7.00 m, what is its speed there, and if it cannot, what is its turning point? VWhat are the (e) magnitude and (f) direction of the force on the particle as it begins to move to the right of x = 5.00 m? Ucr UB UA 4. 6 x (m) 2.
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