The figure shows a plot of potential energy U versus position x of a 0.250 kg particle that can travel only along an x axis under the influence of a conservative force. The graph has these values: UA-9.00 J. Uc-20.0 J and Up-24.0 J. The particle is released at the point where U forms a "potential hill" of "height" UB-12.0J, with kinetic energy 7.50 J. What is the speed of the particle at (a)x -3.50 m and (b)x -6.50 m? What is the position of the turning point on (c) the right side and (d) the left side? W (a) Number (b) Number (c) Number U₂ Su V₂ Units Units Units

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Chapter1: Units, Trigonometry. And Vectors
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The figure displays a plot of potential energy \( U \) versus position \( x \) for a 0.250 kg particle constrained to move along the x-axis under a conservative force. The graph provides the following values: \( U_A = 9.0 \, \text{J} \), \( U_C = 20.0 \, \text{J} \), and \( U_D = 24.0 \, \text{J} \). The particle is released at a point where \( U \) creates a "potential hill" of "height" \( U_B = 12.0 \, \text{J} \), with an initial kinetic energy of 7.0 J. 

Key questions include:

- **(a)** The speed of the particle at \( x = 3.50 \, \text{m} \).
- **(b)** The speed of the particle at \( x = 6.50 \, \text{m} \).
- **(c)** The position of the turning point on the right side.
- **(d)** The position of the turning point on the left side.

### Graph Description

The graph is a plot of \( U(x) \) with several distinct peaks and valleys indicating changes in potential energy as the particle moves along the x-axis. The function appears to have marked changes at specific \( x \)-positions, corresponding to the provided potential energy values at points A, C, and D. The turning points are of particular interest in determining where the kinetic energy of the particle changes direction.
Transcribed Image Text:The figure displays a plot of potential energy \( U \) versus position \( x \) for a 0.250 kg particle constrained to move along the x-axis under a conservative force. The graph provides the following values: \( U_A = 9.0 \, \text{J} \), \( U_C = 20.0 \, \text{J} \), and \( U_D = 24.0 \, \text{J} \). The particle is released at a point where \( U \) creates a "potential hill" of "height" \( U_B = 12.0 \, \text{J} \), with an initial kinetic energy of 7.0 J. Key questions include: - **(a)** The speed of the particle at \( x = 3.50 \, \text{m} \). - **(b)** The speed of the particle at \( x = 6.50 \, \text{m} \). - **(c)** The position of the turning point on the right side. - **(d)** The position of the turning point on the left side. ### Graph Description The graph is a plot of \( U(x) \) with several distinct peaks and valleys indicating changes in potential energy as the particle moves along the x-axis. The function appears to have marked changes at specific \( x \)-positions, corresponding to the provided potential energy values at points A, C, and D. The turning points are of particular interest in determining where the kinetic energy of the particle changes direction.
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