A tennis ball is tossed vertically upwards and travels a distance of 6.5 m in 1.2 seconds. What was the initial velocity of the ball just after it was released?
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A: As per the guidelines first question answered. Kindly post remaining question as new question
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- Between two sufficiently large flat plates charged with opposite charges there is a uniform field pointing from the positively charged plate to the negatively charged one. A small hole is made, in the positive plate, in the inner region (away from the edges) through which an electron can be launched with an initial velocity of modulo v0 making an angle Φ with said plate. a) Find the velocity vector for the electron's motion.An electron is released from rest in a uniform electric field and accelerates to the north at a rate of 115m/s?. Find the magnitude and direction of the electric field.An electron is projected with horizontal velocity of magnitude vo into a constant downward electric field E between two parallel plates. Show that the equation of its trajectory while in the field is given by (shown in the photo attached). where m is the electron's mass and y is its vertical displacement when its horizontal displacement in the field is x.
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- On plant Tehar, the free-fall acceleration is the same as that on Earth but there is als a strong downward electric field that is unyorm close to the planet's surface. A 2.ookg ball having a charge of 6.00 Mc is thrown upward at a speed of 22.0 m/s-and it hits the ground after an interval of 4.505. What is the poten- tial difference between the starting point and the top point of the trajectory 2very urgentWhat is the magnitude of the electric field at a distance of 1.5 m from a pointcharge with Q = 3.5 C?