**Physics Problem: Understanding Free-Fall and Electric Fields on Planet Tehar****Problem Statement:**On planet Tehar, the free-fall acceleration is the same as that on Earth, but there is also a strong downward electric field that is uniform close to the planet's surface. A 2.00 kg ball having a charge of 6.00 μC is thrown upward at a speed of 20.0 m/s and it hits the ground after an interval of 4.50 s. What is the potential difference between the starting point and the top point of the trajectory?**Analysis and Solution:**1. **Free-Fall Acceleration (g):** - Since the free-fall acceleration on planet Tehar is the same as on Earth, we use \( g = 9.8 \, \text{m/s}^2 \).2. **Initial Information:** - Mass of ball, \( m = 2.00 \, \text{kg} \) - Charge of the ball, \( q = 6.00 \, \mu\text{C} = 6.00 \times 10^{-6} \, \text{C} \) - Initial speed, \( v_0 = 20.0 \, \text{m/s} \) - Total time of flight, \( t = 4.50 \, \text{s} \)3. **Trajectory and Time Calculation:** - The ball is thrown upward and returns to the ground, hence the total time for ascending and descending is 4.50 s. - Time to reach the top of the trajectory, \( t_{\text{up}} = \frac{4.50 \, \text{s}}{2} = 2.25 \, \text{s} \)4. **Vertical Displacement Calculation:** - Using the kinematic equation \( v = u + at \): \[ 0 = 20.0 \, \text{m/s} - (9.8 \, \text{m/s}^2) \times 2.25 \, \text{s} \] This confirms the time to the top point as accurate since \( v = 0 \, \text{m/s} \) at the top.5. **Height Calculation (h):** - Using \( h

Answered: Image /qna-images/answer/98bfd942-b6b8-49de-870e-cea5e3153ec3.jpg

On plant Teher, the free-fall acceleration is the same as that on Earth but there is also a strong downward electric field that is unyorm close to the planet's Surface: A 2.ooks Sall having a charge of Charge of 6.00 Mc is thrown upward it a speed of 22.0 m/s. and it hits the ground fter an interval of 4.505. What is the poten- ial difference between the starting point and The top pint of the trajectory 2

On plant Teher, the free-fall acceleration is the same as that on Earth but there is also a strong downward electric field that is unyorm close to the planet's Surface: A 2.ooks Sall having a charge of Charge of 6.00 Mc is thrown upward it a speed of 22.0 m/s. and it hits the ground fter an interval of 4.505. What is the poten- ial difference between the starting point and The top pint of the trajectory 2

College Physics

11th Edition

ISBN:9781305952300

Author:Raymond A. Serway, Chris Vuille

Publisher:Raymond A. Serway, Chris Vuille

Chapter1: Units, Trigonometry. And Vectors

Section: Chapter Questions

Problem 1CQ: Estimate the order of magnitude of the length, in meters, of each of the following; (a) a mouse, (b)...

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