USING GAUSS LAW, PROVE THAT THE ELECTRIC FIELD AT VERY CLOSE POINT FROMA CHARGED CONDUCTOR GIVEN BY THIS RELATION : E
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- uniform electric field of magnitude 28.1N/C is parallel to the x - axis. A circular loop of radius 25.2 cm is centered at the origin with the normal to the loop pointing 39.4° above the x- axis. a) Calculate the electric flux in, newton squared meters per coulomb, through the loop. b) To what angle, in degrees from the positive x - axis, should the normal of the loop be rotated so that the flux through the loop becomes 0.489 N.m2 / C ?Summarize the Gauss’s law results. Give answers in terms of relevant parameters such as enc.: What is the electric field inside a conductor in electrostatic equilibrium?q P The charge per unit length on the thin semicircular wire shown above is A. What is the electric field at the point P?
- a) An insulating sphere carries a charge that is spread uniformly throughout its volume. A con- ducting sphere of the same size carries the same charge, but it is spread over its surface only with no charge in the interior (as it must for a conductor!) Compare the electric fields outside the insulator to the field outside the conductor. Compare the electric fields inside the insulator to the field inside the conductor. (b) Part (a) is an example of a general rule: A charge distributed through some volume will always produce an electric field whose value is a continuous function of position as we cross out of the charge (as we did going from inside to outside of the uniformly charged insulating sphere.) A charge that is distributed across an area (a thin layer of charge with surface charge density o) will produce a field whose value is a DIScontinuous function of position, and the discontinuity is only in the component that is perpendicular to the area and has a value equal to o/eo.…Indicate true or false in each of the following statements: For an isolated positively charged metal plate electric field lines will leave both sides of the plate. v The elctric flux from a surface is the cross product of the electric field vector and the area vector. v Electric field lines start on a positively charged surface. A Gaussian surface can be any closed surface that suites the problem The electric field outside a charged conductor is perpendicular to the surface.Needs Complete solution with 100 % accuracy.
- The figure shows 3 positive pointcharges, at the corners of a square. Thethave Determine the magnitude and direction öf the total electric field at the center of the Square expression for Q =1.0 n Coul and a = l,Ocm, labeled B. Evaluate your Symbolic B.Use Gauss’s law to find the electric field a distance sfrom an infinitely long straight wire, which carries a uniform linear charge density λ.An infinitely long cylindrical conductor of a radius r is charged with a uniformly distributed electrical charge, if the charge per unit length of it equal A coulomb/m. ( using gauss law) calculate the electric field at point d. d.