7. An asteroid is headed towards a starbase. To try and avoid a collision, an explosive device is planted on the asteroid, which breaks it into two pieces, one of which is 2.4 times the mass of the other. Both pieces pass the starbase at the same time. The starbase itself is 2.2 km wide, and the lighter piece of the asteroid passes it 1800 m from one of the starbases edges. Does the other piece of the asteroid hit the starbase?

College Physics
11th Edition
ISBN:9781305952300
Author:Raymond A. Serway, Chris Vuille
Publisher:Raymond A. Serway, Chris Vuille
Chapter1: Units, Trigonometry. And Vectors
Section: Chapter Questions
Problem 1CQ: Estimate the order of magnitude of the length, in meters, of each of the following; (a) a mouse, (b)...
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**Physics Problems and Solutions**

1. **Center of Mass of Carbon Monoxide Molecule**
   - The distance between the centers of carbon and oxygen atoms is \(1.131 \times 10^{-10}\) m. Calculate the center of mass relative to the carbon atom's position.

   - **Given:**
     - Mass of carbon = 12.011 u
     - Mass of oxygen = 16.00 u

   - **Answer:** \(6.46 \times 10^{-11}\) m

2. **Pyramid Volume and Energy Calculations**
   - The Great Pyramid of Cheops originally had a height of \(H = 147\) m and is a square with an edge length \(L = 230\) m. Calculate its volume and energy requirements.

   - **Formula for Volume:** \(V = \frac{1}{3} L^2 H\)

   - It has a uniform density of \(\rho = 1.8 \times 10^3 \text{kg/m}^3\). Calculate:
     - a) The original height of its center of mass.
     - b) The work to lift blocks into place.

   - **Answers:** 
     - a) 36.8 m
     - b) \(1.7 \times 10^{12}\) J

3. **Soda Can Dynamics**
   - Consider a cylindrical soda can with mass \(M\) and height \(H\), initially filled with soda.
   - **Problems:**
     a) Initial center of mass of the can with soda.
     b) Center of mass after soda drains.
     c) Process during draining.
     d) Height of soda at any time (\(y\)) in terms of \(M\), \(H\), and mass unit \(m\).

   - **Answers:**
     - a) \(H/2\)
     - b) \(H/2\)
     - d) \(h = \left(\sqrt{\frac{MH}{m} - M} \right) H\)

4. **Two-Particle System**
   - Two particles: a 3.0 kg particle at a velocity of 6.0 m/s (decreasing y-direction) and a 4.0 kg particle at 7.0 m/s (increasing x-direction). Determine the speed of the system's center of mass
Transcribed Image Text:**Physics Problems and Solutions** 1. **Center of Mass of Carbon Monoxide Molecule** - The distance between the centers of carbon and oxygen atoms is \(1.131 \times 10^{-10}\) m. Calculate the center of mass relative to the carbon atom's position. - **Given:** - Mass of carbon = 12.011 u - Mass of oxygen = 16.00 u - **Answer:** \(6.46 \times 10^{-11}\) m 2. **Pyramid Volume and Energy Calculations** - The Great Pyramid of Cheops originally had a height of \(H = 147\) m and is a square with an edge length \(L = 230\) m. Calculate its volume and energy requirements. - **Formula for Volume:** \(V = \frac{1}{3} L^2 H\) - It has a uniform density of \(\rho = 1.8 \times 10^3 \text{kg/m}^3\). Calculate: - a) The original height of its center of mass. - b) The work to lift blocks into place. - **Answers:** - a) 36.8 m - b) \(1.7 \times 10^{12}\) J 3. **Soda Can Dynamics** - Consider a cylindrical soda can with mass \(M\) and height \(H\), initially filled with soda. - **Problems:** a) Initial center of mass of the can with soda. b) Center of mass after soda drains. c) Process during draining. d) Height of soda at any time (\(y\)) in terms of \(M\), \(H\), and mass unit \(m\). - **Answers:** - a) \(H/2\) - b) \(H/2\) - d) \(h = \left(\sqrt{\frac{MH}{m} - M} \right) H\) 4. **Two-Particle System** - Two particles: a 3.0 kg particle at a velocity of 6.0 m/s (decreasing y-direction) and a 4.0 kg particle at 7.0 m/s (increasing x-direction). Determine the speed of the system's center of mass
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