The factor of safety for a machine element depends on the particular point selected for analysis. For the bar and loading, shown in figure below, we need to have a minimum factor of safety, ηy = 2.5. The bar is to be made of AISI 1050 cold-drawn steel and is loaded by F = 2.65 kN, P = 10.5 kN, and T = 52 N-m.  Draw planar stress elements (A and B) showing normal and shear stresses at their proper orientations. Determine a safe diameter d to the nearest mm, based upon the distortion-energy theory, for both stress elements at A and B of the member shown in the figure.  Determine the safe diameter, d, based on maximum shear stress theory.  You are the designer, and you are to decide on the safe diameter, chosen from one of the diameters obtained from different failure theories used in parts (b) and (c) above, and explain your final decision made on the diameter.

Elements Of Electromagnetics
7th Edition
ISBN:9780190698614
Author:Sadiku, Matthew N. O.
Publisher:Sadiku, Matthew N. O.
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The factor of safety for a machine element depends on the particular point selected for analysis. For the bar and loading, shown in figure below, we need to have a minimum factor of safety, ηy = 2.5. The bar is to be made of AISI 1050 cold-drawn steel and is loaded by F = 2.65 kN, P = 10.5 kN, and T = 52 N-m. 

  1. Draw planar stress elements (A and B) showing normal and shear stresses at their proper orientations.
  2. Determine a safe diameter d to the nearest mm, based upon the distortion-energy theory, for both stress elements at A and B of the member shown in the figure. 
  3. Determine the safe diameter, d, based on maximum shear stress theory. 
  4. You are the designer, and you are to decide on the safe diameter, chosen from one of the diameters obtained from different failure theories used in parts (b) and (c) above, and explain your final decision made on the diameter. 
32M
32T
Obending
T torsion
P.
Tvert.shear = 5
4 L
3А
ахial
A
o' = o - 0,ơp
(o?
+o? + 3t)
%3D
xy
Ssy = 0.5 Sy
y
250 mm
A
B
F
d
T P
Transcribed Image Text:32M 32T Obending T torsion P. Tvert.shear = 5 4 L 3А ахial A o' = o - 0,ơp (o? +o? + 3t) %3D xy Ssy = 0.5 Sy y 250 mm A B F d T P
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