EDThe equilibrium constant, Kp, for the following reaction is 2.01 at 500 K.80PC13(g) + Cl₂(g) PCl5(g)If AH° for this reaction is -87.9 kJ, what is the value of Kp at 589 K?KpSubmit Answer4?000000RFDO LO%5Use the References to access important values if needed for this question.Retry Entire Group 7 more group attempts remainingTCengage Learning Cengage Technical SupportG< 6YH&7UJ8I9KO0LPPreviousEmail Instructor Save and Exit+ 11Next{[}]

We have T1 = 500 KT2 = 589 Kk1 = 2.01k2 = ?ΔH = -87.9 kJ

Answered: The equilibrium constant, Kp, for the…

The equilibrium constant, Kp, for the following reaction is 2.01 at 500 K. PCl3(g) + Cl₂(g) PCI,(g) If AH for this reaction is -87.9 kJ, what is the value of Kp at 589 K?

Chemistry

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ISBN:9781305957404

Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste

Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste

Chapter1: Chemical Foundations

Section: Chapter Questions

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The equilibrium constant, Kp, for the following reaction is 2.01 at 500 K.
80
PC13(g) + Cl₂(g) PCl5(g)
If AH° for this reaction is -87.9 kJ, what is the value of Kp at 589 K?
Kp
Submit Answer
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