The equilibrium constant, K., for the following reaction is 1.05 at 350 K. 2 CH2 Cl2 (g) 2 CH4 (g) + CC4 (g) If an equilibrium mixture of the three gases at 350 K contains 0.0220 M CH2 Cl2 (g) and 0.0158 M CH4, what is the equilibrium concentration of CC4 ? Equilibrium concentration = M
The equilibrium constant, K., for the following reaction is 1.05 at 350 K. 2 CH2 Cl2 (g) 2 CH4 (g) + CC4 (g) If an equilibrium mixture of the three gases at 350 K contains 0.0220 M CH2 Cl2 (g) and 0.0158 M CH4, what is the equilibrium concentration of CC4 ? Equilibrium concentration = M
Chemistry
10th Edition
ISBN:9781305957404
Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Chapter1: Chemical Foundations
Section: Chapter Questions
Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...
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![**Equilibrium Constant and Concentration Calculation**
The equilibrium constant, \( K_c \), for the following reaction is 1.05 at 350 K.
\[ 2 \, \text{CH}_2\text{Cl}_2 (g) \rightleftharpoons \text{CH}_4(g) + \text{CCl}_4(g) \]
If an equilibrium mixture of the three gases at 350 K contains 0.0220 M \( \text{CH}_2\text{Cl}_2(g) \) and 0.0158 M \( \text{CH}_4(g) \), what is the equilibrium concentration of \( \text{CCl}_4 \)?
Equilibrium concentration = \(\underline{\phantom{M}}\) M](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F4e0231ae-cda3-47d6-8f66-a62cbb6b7daa%2F616ad346-d64c-4122-9a60-c425a25b4c7a%2Fmfp62u_processed.png&w=3840&q=75)
Transcribed Image Text:**Equilibrium Constant and Concentration Calculation**
The equilibrium constant, \( K_c \), for the following reaction is 1.05 at 350 K.
\[ 2 \, \text{CH}_2\text{Cl}_2 (g) \rightleftharpoons \text{CH}_4(g) + \text{CCl}_4(g) \]
If an equilibrium mixture of the three gases at 350 K contains 0.0220 M \( \text{CH}_2\text{Cl}_2(g) \) and 0.0158 M \( \text{CH}_4(g) \), what is the equilibrium concentration of \( \text{CCl}_4 \)?
Equilibrium concentration = \(\underline{\phantom{M}}\) M
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