The energies, E, for the first few states of an unknown element are given in the table in arbitrary units. n 1 2 3 4 00 ... E -63 -27 -12 -9 A gaseous sample of this element is bombarded by photons of various energies in these same units. Match each photon to the result of its absorption, or lack thereof, by an n = 1 electron.

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Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
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Chapter1: Chemical Foundations
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Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...
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The energies, E, for the first few states of an unknown element are given in the table in arbitrary units.
n
1
2
3
4
E
-63
-27
-12
-9
...
A gaseous sample of this element is bombarded by photons of various energies in these same units.
Match each photon to the result of its absorption, or lack thereof, by an n = 1 electron.
Answer Bank
Photon
Energy
Result
n = 1 to n = 4
A
63
n = 1 to n = 3
В
51
n = 1 to n=2
C
47
electron ejected
D
36
not absorbed
8
Transcribed Image Text:The energies, E, for the first few states of an unknown element are given in the table in arbitrary units. n 1 2 3 4 E -63 -27 -12 -9 ... A gaseous sample of this element is bombarded by photons of various energies in these same units. Match each photon to the result of its absorption, or lack thereof, by an n = 1 electron. Answer Bank Photon Energy Result n = 1 to n = 4 A 63 n = 1 to n = 3 В 51 n = 1 to n=2 C 47 electron ejected D 36 not absorbed 8
Expert Solution
Step 1

This is an quantum mechanical thing .To understand this we must consider the photon the as an energy packege.At a perticular energy the photon will go to one state to another state ,otherwise other energy will not absorbed.

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