The efficiency ratio for a steel specimen immersed in a phosphating tank is the weight of the phosphate coating divided by the metal loss (both in mg/ft2). An article gave the accompanyingdata on tank temperature (x) and efficiency ratio (y).stemTemp. 170 172 173 174 174 175Ratio 0.85 1.30 1.42 1.03 1.07 1.08Temp. 181 181 181 182 182 182 183 184 184 185 186 188Ratio 2.15 0.85 1.43 0.91 1.81 1.94 2.68 1.49 2.52 3.013.01 1.871.87 3.08(a) Construct a stem-and-leaf display of temperature. (Split the stems, placing leaves 0 to 1 on the first stem, leaves 2 to 3 on the second stem, etc. Enter numbers from smallest to largestseparated by spaces. Enter NONE for stems with no values.)17 017 2317 44517 671817 NONEUSE SALT18 000011118 2223445leaf18 618 8176 177 180 180 180 1801.04 1.80 1.45 1.60 1.61 2.13Comment on interesting features.The distribution is approximately symmetric and the variation is smallConstruct a stem-and-leaf display of efficiency ratio. (Trucate the hundredths digit and split the stems, placing leaves 0 to 1 on the first stem, leaves 2 to 3 on the second stem, etc.Enter numbers from smallest to largest separated by spaces. Enter NONE for stems with no values.) stem000001111222233leafComment on interesting features.The distribution is positively skewedand the variation is ---Select--- .(b) Is the value of efficiency ratio completely and uniquely determined by tank temperature? Explain your reasoning.The efficiency ratio is not ✓ uniquely determined by temperature since there is data with equal temperatures associated with differentefficiency ratios.

Stem and leaf plot : It is a method to represent the data. Data divided into two parts ( stems and…

Answered: The efficiency ratio for a steel…

MATLAB: An Introduction with Applications

6th Edition

ISBN:9781119256830

Author:Amos Gilat

Publisher:Amos Gilat

Chapter1: Starting With Matlab

Section: Chapter Questions

Problem 1P

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The efficiency for a steel specimen immersed in a phosphating tank is the weight of the phosphate coating divided by the metal loss (both in mg/ft?). An article gave the accompanying data on tank temperature (x) and efficiency ratio (y). Temp. 173 175 176 177 177 178 179 180 Ratio 0.94 1.21 1.44 1.05 1.09 1.02 0.96 1.88 Temp. 183 183 183 183 183 184 184 185 Ratio 1.53 1.50 1.57 2.07 2.05 0.86 1.53 0.80 Temp. 185 185 185 187 187 188 189 191 Ratio 1.71 1.96 2.76 1.59 2.60 3.10 1.81 3.18 In USE SALT (a) Determine the equation of the estimated regression line. (Round all numerical values to four decimal places.) (b) Calculate a point estimate for true average efficiency ratio when tank temperature is 185. (Round your answer to four decimal places.) (c) Calculate the values of the residuals from the least squares line for the four observations for which temperature is 185. (Round your answers to two decimal places.) (185, 0.80) (185, 1.71) (185, 1.96) (185, 2.76) Why do they not all have…
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