The efficiency ratio for a steel specimen immersed in a phosphating tank is the weight of the phosphate coating divided by the metal loss (both in mg/ft2). An article gave the accompanyin data on tank temperature (x) and efficiency ratio (y). Temp. 170 172 173 174 174 175 176 177 180 180 180 180 Ratio 0.85 1.30 1.42 1.03 1.07 1.08 1.04 1.04 1.80 1.45 1.60 1.61 2.13 Temp. 181 181 181 182 182. 182 183 184 184 185 186 188.
The efficiency ratio for a steel specimen immersed in a phosphating tank is the weight of the phosphate coating divided by the metal loss (both in mg/ft2). An article gave the accompanyin data on tank temperature (x) and efficiency ratio (y). Temp. 170 172 173 174 174 175 176 177 180 180 180 180 Ratio 0.85 1.30 1.42 1.03 1.07 1.08 1.04 1.04 1.80 1.45 1.60 1.61 2.13 Temp. 181 181 181 182 182. 182 183 184 184 185 186 188.
MATLAB: An Introduction with Applications
6th Edition
ISBN:9781119256830
Author:Amos Gilat
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Chapter1: Starting With Matlab
Section: Chapter Questions
Problem 1P
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Transcribed Image Text:The efficiency ratio for a steel specimen immersed in a phosphating tank is the weight of the phosphate coating divided by the metal loss (both in mg/ft2). An article gave the accompanying
data on tank temperature (x) and efficiency ratio (y).
stem
Temp. 170 172 173 174 174 175
Ratio 0.85 1.30 1.42 1.03 1.07 1.08
Temp. 181 181 181 182 182 182 183 184 184 185 186 188
Ratio 2.15 0.85 1.43 0.91 1.81 1.94 2.68 1.49 2.52 3.01
3.01 1.87
1.87 3.08
(a) Construct a stem-and-leaf display of temperature. (Split the stems, placing leaves 0 to 1 on the first stem, leaves 2 to 3 on the second stem, etc. Enter numbers from smallest to largest
separated by spaces. Enter NONE for stems with no values.)
17 0
17 23
17 445
17 67
18
17 NONE
USE SALT
18 0000111
18 2223
445
leaf
18 6
18 8
176 177 180 180 180 180
1.04 1.80 1.45 1.60 1.61 2.13
Comment on interesting features.
The distribution is approximately symmetric and the variation is small
Construct a stem-and-leaf display of efficiency ratio. (Trucate the hundredths digit and split the stems, placing leaves 0 to 1 on the first stem, leaves 2 to 3 on the second stem, etc.
Enter numbers from smallest to largest separated by spaces. Enter NONE for stems with no values.)

Transcribed Image Text:stem
0
0
0
0
0
1
1
1
1
2
2
2
2
3
3
leaf
Comment on interesting features.
The distribution is positively skewed
and the variation is ---Select--- .
(b) Is the value of efficiency ratio completely and uniquely determined by tank temperature? Explain your reasoning.
The efficiency ratio is not ✓ uniquely determined by temperature since there is data with equal temperatures associated with different
efficiency ratios.
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