Temp. 173 175 176 177 177 178 179 180 Ratio 0.76 1.23 1.44 0.95 1.01 1.02 1.10 1.84 Temp. 183 183 183 183 183 184 184 185 Ratio 1.49 1.66 1.55 2.03 2.17 0.76 1.39 0.94 Temp. 185 185 185 187 187 188 189 191 Ratio 1.73 1.96 2.58 1.45 2.56 3.02 1.97 3.16 A USE SALT Determine the equation of the estimated regression Iline. (Round all numerical values to four decimal places.)
Temp. 173 175 176 177 177 178 179 180 Ratio 0.76 1.23 1.44 0.95 1.01 1.02 1.10 1.84 Temp. 183 183 183 183 183 184 184 185 Ratio 1.49 1.66 1.55 2.03 2.17 0.76 1.39 0.94 Temp. 185 185 185 187 187 188 189 191 Ratio 1.73 1.96 2.58 1.45 2.56 3.02 1.97 3.16 A USE SALT Determine the equation of the estimated regression Iline. (Round all numerical values to four decimal places.)
MATLAB: An Introduction with Applications
6th Edition
ISBN:9781119256830
Author:Amos Gilat
Publisher:Amos Gilat
Chapter1: Starting With Matlab
Section: Chapter Questions
Problem 1P
Related questions
Question
![The efficiency for a steel specimen immersed in a phosphating tank is the weight of the phosphate coating divided by the metal loss (both in mg/ft²). An article provided the accompanying data on tank temperature (\(x\)) and efficiency ratio (\(y\)).
A table with two columns shows the data:
- **Temp.**: 173, 175, 176, 177, 178, 179, 180, 183, 183, 183, 183, 184, 184, 185, 185, 185, 187, 187, 188, 189, 191
- **Ratio**: 0.76, 1.23, 1.44, 0.95, 1.01, 1.02, 1.10, 1.84, 1.49, 1.66, 1.55, 2.03, 2.17, 0.76, 1.39, 0.94, 1.73, 1.96, 2.58, 1.45, 2.56, 3.02, 1.97, 3.16
**Tasks:**
(a) **Determine the equation of the estimated regression line.** (Round all numerical values to four decimal places.)
\[ y = \_\_\_\_ \]
(b) **Calculate a point estimate for true average efficiency ratio when tank temperature is 185.** (Round your answer to four decimal places.)
\[ \_\_\_\_ \]
(c) **Calculate the values of the residuals from the least squares line for the four observations for which temperature is 185.** (Round your answers to two decimal places.)
- (185, 0.94): \_\_\_
- (185, 1.73): \_\_\_
- (185, 1.96): \_\_\_
- (185, 2.58): \_\_\_
**Why do they not all have the same sign?**
- [ ] These residuals do not all have the same sign because in the case of the second pair of observations, the observed efficiency ratio was equal to the predicted value. In the cases of the other pairs of observations, the observed efficiency ratios were larger than the predicted value.
- [ ] These residuals do not all have the same](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2Ffea4cb18-f853-4dd5-87f1-44780e7d8dd9%2F48387b3e-ab60-4898-8578-fef508b0a835%2Fjgs1az9_processed.png&w=3840&q=75)
Transcribed Image Text:The efficiency for a steel specimen immersed in a phosphating tank is the weight of the phosphate coating divided by the metal loss (both in mg/ft²). An article provided the accompanying data on tank temperature (\(x\)) and efficiency ratio (\(y\)).
A table with two columns shows the data:
- **Temp.**: 173, 175, 176, 177, 178, 179, 180, 183, 183, 183, 183, 184, 184, 185, 185, 185, 187, 187, 188, 189, 191
- **Ratio**: 0.76, 1.23, 1.44, 0.95, 1.01, 1.02, 1.10, 1.84, 1.49, 1.66, 1.55, 2.03, 2.17, 0.76, 1.39, 0.94, 1.73, 1.96, 2.58, 1.45, 2.56, 3.02, 1.97, 3.16
**Tasks:**
(a) **Determine the equation of the estimated regression line.** (Round all numerical values to four decimal places.)
\[ y = \_\_\_\_ \]
(b) **Calculate a point estimate for true average efficiency ratio when tank temperature is 185.** (Round your answer to four decimal places.)
\[ \_\_\_\_ \]
(c) **Calculate the values of the residuals from the least squares line for the four observations for which temperature is 185.** (Round your answers to two decimal places.)
- (185, 0.94): \_\_\_
- (185, 1.73): \_\_\_
- (185, 1.96): \_\_\_
- (185, 2.58): \_\_\_
**Why do they not all have the same sign?**
- [ ] These residuals do not all have the same sign because in the case of the second pair of observations, the observed efficiency ratio was equal to the predicted value. In the cases of the other pairs of observations, the observed efficiency ratios were larger than the predicted value.
- [ ] These residuals do not all have the same
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