Hello! I can't seem to figure out how to do this problem, I've worked it out twice and I keep on getting the same answers. Any help would be appreciated! **Title: Understanding Magnetic Fields Around Perpendicular Current-Carrying Wires****Introduction**In this exercise, we analyze the magnetic fields generated by two perpendicular, long, straight wires that lie in the plane of the paper. The current (I) flowing through each wire is 3.5 A. Our task is to find the magnitudes of the net magnetic fields at designated points A and B.**Given Data**- Current in wires (I): 3.5 A- Horizontal distance (\(d_H\)): 0.10 m- Vertical distance (\(d_V\)): 0.49 m**Objective**Calculate the net magnetic field (\(B_{\text{net}}\)) at points A and B.**Visual Diagram Explanation**The diagram illustrates two intersecting wires:- One wire is oriented vertically, extending up and down.- The other wire is oriented horizontally, stretching left to right.- Point A is positioned above the horizontal wire at a distance \(d_V\) and to the right at a distance \(d_H\).- Point B is located below the horizontal wire at a distance \(d_H\) and to the left at a distance \(d_V\).**Solution Details***Net Magnetic Field Calculations:*- \(B_{\text{net}}\) at point A: \(7 \times 10^{-5}\) T- \(B_{\text{net}}\) at point B: \(1.428 \times 10^{-5}\) T**Attempts**There have been 2 out of a total of 6 possible attempts used to provide the answers.**Conclusion**Understanding the magnetic field interactions at points around current-carrying wires is crucial for comprehending electromagnetic fields. This exercise demonstrates the calculation of magnetic field magnitudes using given distances and current values.

Given data- current in each wire=3.5 A dh=0.10 m, dv=0.49 m

The drawing shows two perpendicular, long, straight wires, both of which lie in the plane of the paper. The current in each of the wires is l= 3.5 A. In the drawing du = 0.10 m and dy = 0.49 m. Find the magnitudes of the net magnetic fields at points A and B. dv B dy i 7E-5 Bnet at point A = i 1.428E-5 Bnet at point B =

The drawing shows two perpendicular, long, straight wires, both of which lie in the plane of the paper. The current in each of the wires is l= 3.5 A. In the drawing du = 0.10 m and dy = 0.49 m. Find the magnitudes of the net magnetic fields at points A and B. dv B dy i 7E-5 Bnet at point A = i 1.428E-5 Bnet at point B =

College Physics

11th Edition

ISBN:9781305952300

Author:Raymond A. Serway, Chris Vuille

Publisher:Raymond A. Serway, Chris Vuille

Chapter1: Units, Trigonometry. And Vectors

Section: Chapter Questions

Problem 1CQ: Estimate the order of magnitude of the length, in meters, of each of the following; (a) a mouse, (b)...

See similar textbooks

Similar questions

1. A pregnant woman experiences labor pains, so the husband decided that she will be brought to the nearest hospital, 70 kilometers away. Accordingly, her wife delivered the baby after an hour. Suppose the car that was used to bring the pregnant woman has a speed of 50 km/h. Assume that the speed of light is 60 km/h, will the pregnant woman reach the hospital? Prove your answer with numerical solution.
1 ô'z is the mean value of E. Using this result and the definition of o = E² - (E)'. z oß Show that E?
Echoes return in 2.5 secs to a person standing in front of a cliff. How far away is the cliff? The speed of sound in air at sea level is 343 m/s when the temp is 200 degrees celsius For question 3 & 4: A student throws a ball vertically upward such that is travels 9.0 m to its maximum height. If the ball is caught at the initial height 2'4 secs after being thrown, What is the ball's average velocity?Find the average velocity. 7.5 m/s0 m/s3.75 m/s A drag racer starting from rest accelerates in a straight line at a constant rate of 5.5 m/s^2 for 6 secs. What is the racer' velocity at the end of the given time? Where would you place a 50 kg mass on a 75 kg 14 meters rod so that its center of mass os 1 meter to the left of the physical center of the rod?
I did not understand this subject very well. (Average velocity, instantaneous velocity, average acceleration, instantaneous acceleration) And I am trying to understand with this question. Especially I can't get the "instantaneous" formulas in my head and I can't figure out why we did it. I would be happy if you could solve it in an explanatory way. Thanks.
That's what I thought too! But the answer choices it gave were 8 m/s, 4 m/s, 2 m/s, and 6 m/s so I'm confused. I went with 8 and it was wrong.
Help me understand physics notes?
Nilo
Please calculate the cars acceleration and the cars final speed, don’t refer to my writing in both parts, disregard it, just look at the information above 1 and 2
Imagine you derive the following expression by analyzing the physics of a particular system: v2=v20+2axv2=v02+2ax. The problem requires solving for xx, and the known values for the system are a=2.55meter/second2a=2.55meter/second2, v0=21.8meter/secondv0=21.8meter/second, and v=0meter/secondv=0meter/second. Perform the next step in the analysis.
I need help with a math question: Given that x = position, v = velocity, a = acceleration, m = mass. Which of the following will have units of kg * m/s^2 and why? m ∫ a dt m ∫ v dt 1/2m dv^2/dx m ∫ x dt 1/2m dv^2/dt m dx/dt m dv/dt m da/dt 1/2m ∫ v^2 dt I am including an image/reference table. Thanks!