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The drawing shows a skateboarder moving at 6.20 m/s along a horizontal section of a track that is slanted upward by 0 = 48.0° above the horizontal at its end, which is 0.580 m above the ground. When she leaves the track, she follows the characteristic path of projectile motion. Ignoring friction and air resistance, find the maximum height H to which she rises above the end of the track. 6.20m/s 0.580m

The drawing shows a skateboarder moving at 6.20 m/s along a horizontal section of a track that is slanted upward by 0 = 48.0° above the horizontal at its end, which is 0.580 m above the ground. When she leaves the track, she follows the characteristic path of projectile motion. Ignoring friction and air resistance, find the maximum height H to which she rises above the end of the track. 6.20m/s 0.580m

College Physics
College Physics
11th Edition
ISBN:9781305952300
Author:Raymond A. Serway, Chris Vuille
Publisher:Raymond A. Serway, Chris Vuille
Chapter1: Units, Trigonometry. And Vectors
Section: Chapter Questions
Problem 1CQ: Estimate the order of magnitude of the length, in meters, of each of the following; (a) a mouse, (b)...
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The drawing shows a skateboarder moving at 6.20 m/s along a horizontal section of a track that is slanted upward by θ = 48.0° above the horizontal at its end, which is 0.580 m above the ground. When she leaves the track, she follows the characteristic path of projectile motion. Ignoring friction and air resistance, find the maximum height H to which she rises above the end of the track. In the diagram, a skateboarder is depicted on a curved track. The initial velocity is labeled as 6.20 m/s. The track ends at a slope with an angle θ of 48.0° and a vertical height of 0.580 m. The path of the skateboarder after leaving the track is shown as a parabolic trajectory, with the maximum height H to be determined. Number: 1.0831 Units: m
Transcribed Image Text:The drawing shows a skateboarder moving at 6.20 m/s along a horizontal section of a track that is slanted upward by θ = 48.0° above the horizontal at its end, which is 0.580 m above the ground. When she leaves the track, she follows the characteristic path of projectile motion. Ignoring friction and air resistance, find the maximum height H to which she rises above the end of the track. In the diagram, a skateboarder is depicted on a curved track. The initial velocity is labeled as 6.20 m/s. The track ends at a slope with an angle θ of 48.0° and a vertical height of 0.580 m. The path of the skateboarder after leaving the track is shown as a parabolic trajectory, with the maximum height H to be determined. Number: 1.0831 Units: m
Expert Solution
Step 1

Given data:

The speed of the skater v=6.20 m/s

The height reached by the skater is h=0.580 m

The angle θ=48.0°

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