The electric field of an electromagnetic wave propagating through a vacuum Is given by: E = 250 sin (2nx101²t – n × 10*z) î en V/m. a. The direction of wave propagation b. Wavelength c. The expression of the corresponding magnetic field

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Chapter1: Units, Trigonometry. And Vectors
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The electric field of an electromagnetic
wave propagating through a
vacuum
Is given by:
2
E = 250 sin (2nx1012t – n × 10*z)î en V/m.
The direction of wave propagation
b. Wavelength
c. The expression of the corresponding
magnetic field
d. The intensity of the radiation it
carries
e. The energy in eV that it transports
through a square surface of 40 cm sideways
for half an hour.
Transcribed Image Text:The electric field of an electromagnetic wave propagating through a vacuum Is given by: 2 E = 250 sin (2nx1012t – n × 10*z)î en V/m. The direction of wave propagation b. Wavelength c. The expression of the corresponding magnetic field d. The intensity of the radiation it carries e. The energy in eV that it transports through a square surface of 40 cm sideways for half an hour.
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