1. For a simple capacitor with two flat plates, the capacitance (C) [F] can be calculated by 6,60A C = d where 80 = 8,854 x 10-12 [F/m] (the permittivity of free space in farads per meter) &, = relative static permittivity, a property of the insulator [dimensionless] A = area of overlap of the plates [m2] d distance between the plates [m] Several experimental capacitors were fabricated with different plate areas (A), but with the same inter-plate distance (d = 1.2 mm) and the same insulating material, and thus the same relative static permittivity (ɛ,). The capacitance of each device was measured and plotted versus the plate area. The graph and trendline follow. The numeric scales were deliberately omitted. Jom C = 19.15 A Plate Area (A) [m2] (a) What are the units of the slope (19.15)? (b) If the capacitance is 3 nanofarads [nF], what is the area (A) of the plates? (c) What is the relative static permittivity of the insulating layer? (d) If the distance between the plates were doubled, how would the capacitance be affected? Capacitance (C) [nF]
1. For a simple capacitor with two flat plates, the capacitance (C) [F] can be calculated by 6,60A C = d where 80 = 8,854 x 10-12 [F/m] (the permittivity of free space in farads per meter) &, = relative static permittivity, a property of the insulator [dimensionless] A = area of overlap of the plates [m2] d distance between the plates [m] Several experimental capacitors were fabricated with different plate areas (A), but with the same inter-plate distance (d = 1.2 mm) and the same insulating material, and thus the same relative static permittivity (ɛ,). The capacitance of each device was measured and plotted versus the plate area. The graph and trendline follow. The numeric scales were deliberately omitted. Jom C = 19.15 A Plate Area (A) [m2] (a) What are the units of the slope (19.15)? (b) If the capacitance is 3 nanofarads [nF], what is the area (A) of the plates? (c) What is the relative static permittivity of the insulating layer? (d) If the distance between the plates were doubled, how would the capacitance be affected? Capacitance (C) [nF]
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![1. For a simple capacitor with two flat plates, the capacitance (C) [F] can be calculated by
6,60A
C =
d
where
= 8.854 x 10-12 [F/m] (the permittivity of free space in farads
8, = relative static permittivity, a property of the insulator [dimensionless]
A = area of overlap of the plates [m2]
d = distance between the plates [m]
per meter)
me
Several experimental capacitors were fabricated with different plate areas (A), but
with the same inter-plate distance (d = 1.2 mm) and the same insulating material, and
thus the same relative static permittivity (ɛ,). The capacitance of each device was measured
and plotted versus the plate area. The graph and trendline follow. The numeric scales were
llol sds deliberately omitted.
C = 19.15 A
Plate Area (A) [m²]
(a) What are the units of the slope (19.15)?
(b) If the capacitance is 3 nanofarads [nF], what is the area (A) of the plates?
(c) What is the relative static permittivity of the insulating layer?
(d) If the distance between the plates were doubled, how would the capacitance be
affected?
Capacitance (C) [nF]](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F94bb715a-53b2-429a-957c-6b50bc881438%2Fc97e232c-b726-4a1d-98b4-e4739bfd4bb6%2F3bpdn55_processed.jpeg&w=3840&q=75)
Transcribed Image Text:1. For a simple capacitor with two flat plates, the capacitance (C) [F] can be calculated by
6,60A
C =
d
where
= 8.854 x 10-12 [F/m] (the permittivity of free space in farads
8, = relative static permittivity, a property of the insulator [dimensionless]
A = area of overlap of the plates [m2]
d = distance between the plates [m]
per meter)
me
Several experimental capacitors were fabricated with different plate areas (A), but
with the same inter-plate distance (d = 1.2 mm) and the same insulating material, and
thus the same relative static permittivity (ɛ,). The capacitance of each device was measured
and plotted versus the plate area. The graph and trendline follow. The numeric scales were
llol sds deliberately omitted.
C = 19.15 A
Plate Area (A) [m²]
(a) What are the units of the slope (19.15)?
(b) If the capacitance is 3 nanofarads [nF], what is the area (A) of the plates?
(c) What is the relative static permittivity of the insulating layer?
(d) If the distance between the plates were doubled, how would the capacitance be
affected?
Capacitance (C) [nF]
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