An object is launched at a velocity of 20 m/s in a direction making an angle of 30° upward with the horizontal. Calculate the time to reach its maximum height. Use for gravity acceleration the value 10. Do not include units of measure in the result.

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QUESTION 4
An object is launched at a velocity of 20 m/s in a direction making an angle of 30° upward with the horizontal. Calculate the
time to reach its maximum height. Use for gravity acceleration the value 10. Do not include units of measure in the result.
Sin30° = 0.5
Cos30° = 0.87
Transcribed Image Text:QUESTION 4 An object is launched at a velocity of 20 m/s in a direction making an angle of 30° upward with the horizontal. Calculate the time to reach its maximum height. Use for gravity acceleration the value 10. Do not include units of measure in the result. Sin30° = 0.5 Cos30° = 0.87
Expert Solution
Step 1

Given data

The velocity of the object launch is v=20 m/s

The angle of the projectile is θ=30o

The accleration due to gravity is g=10 m/s2

The time to reach the maximum height is half of the total time of flight.

The time of flight is,

T=2vsinθg=220 m/ssin 30o10 m/s2=2 s

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