Answered: The double T-beam is fabricated by…

The double T-beam is fabricated by welding three plates together as shown, determine the shear flow around the weld to support a shear V = 4.358 kg. Data: Width of skate bf = 46 cm

Steel Design (Activate Learning with these NEW titles from Engineering!)

6th Edition

ISBN:9781337094740

Author:Segui, William T.

Publisher:Segui, William T.

Chapter3: Tension Members

Section: Chapter Questions

Problem 3.3.8P

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4.) A 150 x 90 x 12 angular section is welded to a gusset plate as shown in the figure. The angle is A36 steel with FY=248 MPa. The weld is E 80 electrode with Fu = 550 MPa. The allowable tensile stress for the angle is 0.6Fy and the allowable shear stress for the weld is 0.3Fu. The Area of the angular section is 2751 sq.mm. with y=51mm. CS 56 Which of the following most nearly gives the design force P? a.) 400,365.9 N b.) 409,348.8 N c.) 412,793.5 N d.) 420,366.6 N 5.) A W350 x 90 steel is used as a simply supported beam 8m long. The beam carries three equal concentrated loads at every quarter points. It also carries a uniform dead load o 5 kn/m (including its own weight) and a uniform live load of 7.20 kn/m. Properties of W 350 x 90 steel: bf = 250 mm The allowable bending stress is 0.66Fy. The allowable shear stress is 0.40Fy. The allowable deflection is L/360. Use Fx=248 Mpa and E=200 Gpa. tf = 16.40 mm V d = 350 mm Determine the maximum value of each concentrated load based on…
The double T-beam is fabricated by welding the three plates together as shown. Part A Determine the shear stress in the weld necessary to support a shear force of V=78 kN�=78 kN.
Situation 5. The angular section shown below is welded to a 12 mm gusset plate. Both materials are A36 steel with Fy = 250 MPa. The allowable tensile stress is 0.6Fy. The weld is E80 Electrode and 12 mm thickness. INNOVATIONS Properties of L 150x90x12: y = 50 shear stress of weld = 0.3Fu A = 2750 Allowable REVIEW INNOVATIE a K ➜ www A. 234 KN B. 349 KN b 13. What is the value of P without exceeding the allowable tensile the angle? C. 382 kN p. 413 kN 14. Find required length of the weld based on shear? A. 280 mm C. 300 mm D. 380 mm B. 320 mm 15. Find the required value of a? A. 108 mm B. 97.9 mm D. 185 mm NEW INNOVATIONS REVIEW INNOVATIOf REVIEW NEW INNOVATIONS
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