3. The aluminum block has the rectangular cross-section and is subjected to an axial compressive force of 8 kips. The 1.5-in side changed its length to 1.50014 inches. Use E = 10 x 10° ksi. Calculate the new length of the 2-inch side. Answer: Lew = 2.00019 in 1.5 in 2 in. 8 kip- 8 kip 3 in.
3. The aluminum block has the rectangular cross-section and is subjected to an axial compressive force of 8 kips. The 1.5-in side changed its length to 1.50014 inches. Use E = 10 x 10° ksi. Calculate the new length of the 2-inch side. Answer: Lew = 2.00019 in 1.5 in 2 in. 8 kip- 8 kip 3 in.
Chapter2: Loads On Structures
Section: Chapter Questions
Problem 1P
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![3. The aluminum block has the rectangular cross-section and is subjected to an axial compressive force
of 8 kips. The 1.5-in side changed its length to 1.50014 inches. Use E = 10 x 10° ksi. Calculate the new
Answer: Lnew = 2.00019 in
length of the 2-inch side.
1.5 in
2 in.
8 kip-
8 kip
3 in.](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F05d0b0f0-532a-4fe9-85ac-ab240cc14959%2F7c424dc0-990d-42d5-bd82-2527a2b0e80a%2Fec7rotn_processed.png&w=3840&q=75)
Transcribed Image Text:3. The aluminum block has the rectangular cross-section and is subjected to an axial compressive force
of 8 kips. The 1.5-in side changed its length to 1.50014 inches. Use E = 10 x 10° ksi. Calculate the new
Answer: Lnew = 2.00019 in
length of the 2-inch side.
1.5 in
2 in.
8 kip-
8 kip
3 in.
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