Important InformationAtomic Masses (g/mol): H = 1.01, C = 12.01, N = 14.01, O = 16.00,%3D%3DNe = 20.18, CI = 35.45, K = 39.10, Ar = 39.95,Cu = 63.55, Ag = 107.87wwmConstants:R = 8.314 J/mol:K = 0.08206 L·atm/mol·Kw wwwF= 96,485 C/mol = 96,485 J/V-mol%D 9.The dissolution reactions of gold (Au) in 1M HNO3 and 1M aqua regia (1M HNO3 + 1M HCI) aregiven below.Au(s) + NO3+ 4 H+,(aq)→ Au3+(аq)+ NO(9) + 2 H20(1)(1)(аq)Au(s) + NO3+ 4 H* (aq)(aq)+ 4 Cl (aq)→ AuCl4"+ NO(9) + 2 H200(2)(аq)(g)Reduction Half – ReactionE° (V)-Au3+ + 3 e- 2 Au1.36AuCl4¯ + 3 e¯ → Au + 4 Cl-1.00NO3- + 4 H* + 3 e¯ → NO + 2 H200.962 H30* + 2 e-= H2 + 2 H209. a) Calculate E°cell and Keg for the dissolution of gold in 1M HNO3 under standard conditions.9. b) Calculate E°cell and Keg for the dissolution of gold in aqua regia under standard conditions.9. c) Using the values calculated in a) and b), determine the formation constant (K;) of AuCla".The formation reaction is given below. [Hint, express Kf as a function of the Keg values from a)and b)].3+Aušt (aa) + 4 Cl¯(ад)→ AuCl4(aq)

Whenever there is a reversal in the direction of reaction , the concerning Eo value gets changed.

The dissolution reactions of gold (Au) in 1M HNO3 and 1M aqua regia (1M HNO3 + 1M HCI) are given below. + N03 + 4 H* (aq) (ад) Au** (aq) + NO (g) +2 H20(1) Au(s) (1) Au(s) + NO3 + 4 H+, (aq) +4 Cl¯ (aq) AuCl4 + NO (g) (aq) + 2 H201) (2) (аq) Reduction Half – Reaction E° (V) Au3+ + 3 e¯ = Au 1.36 АuCly + 3 е — Аи + 4 cI- 1.00 NO3 + 4 H* + 3 e¯ → NO +2 H20 0.96 2 H30* + 2 e¯ = H2 +2 H20 Calculate E°cell and Keg for the dissolution of gold in 1M HNO3 under standard conditions. Calculate E°, cell and Keg for the dissolution of gold in aqua regia under standard conditions. Using the values calculated in a) and b), determine the formation constant (K;) of AuCl4. The formation reaction is given below. [Hint, express Kf as a function of the Keg values from a) and b)]. + 4 Cl (aq) (ад) AuCl4 (aq) Au³+

The dissolution reactions of gold (Au) in 1M HNO3 and 1M aqua regia (1M HNO3 + 1M HCI) are given below. + N03 + 4 H* (aq) (ад) Au** (aq) + NO (g) +2 H20(1) Au(s) (1) Au(s) + NO3 + 4 H+, (aq) +4 Cl¯ (aq) AuCl4 + NO (g) (aq) + 2 H201) (2) (аq) Reduction Half – Reaction E° (V) Au3+ + 3 e¯ = Au 1.36 АuCly + 3 е — Аи + 4 cI- 1.00 NO3 + 4 H* + 3 e¯ → NO +2 H20 0.96 2 H30* + 2 e¯ = H2 +2 H20 Calculate E°cell and Keg for the dissolution of gold in 1M HNO3 under standard conditions. Calculate E°, cell and Keg for the dissolution of gold in aqua regia under standard conditions. Using the values calculated in a) and b), determine the formation constant (K;) of AuCl4. The formation reaction is given below. [Hint, express Kf as a function of the Keg values from a) and b)]. + 4 Cl (aq) (ад) AuCl4 (aq) Au³+

Chemistry

10th Edition

ISBN:9781305957404

Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste

Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste

Chapter1: Chemical Foundations

Section: Chapter Questions

Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...

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