Chemistry
10th Edition
ISBN:9781305957404
Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Chapter1: Chemical Foundations
Section: Chapter Questions
Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...
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![5. Erina observed that the borax she uses to clean the house is only partially soluble with
water. She found on the internet that borax is composed of sodium tetraborate
(Na,B,0;(OH), • 8H,0) and wanted to analyze its solubility. The dissolution of borax is:
Na,B,0;(OH), • 8H20(9 = 2 Na (aq) + B40;(OH), (aq) + 8 H20o
A 50.0 mL saturated solution was prepared for the experiment. After filtering the solution,
a 5.00 mL aliquot was transferred to a 25.0 mL Erlenmeyer flask and was titrated using
pre-standardized 0.4320 M HCI. The endpoint was reached after the addition of 4.73 mL
titrant.
Since the tetraborate anion (B,0;(OH),?) is a weak base, the tetraborate ion reacts with
HCI by the reaction:
B,0,(OH), (aq) + 2 H*(aq) + 3 H,0g = 4 H;BO3(aq)
a. Write the K, expression for the dissolution process.](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F595e835f-079c-445a-95d1-bd00de829254%2Fa17b111b-edb0-41a6-a8c0-104ddeae3300%2F63jm97_processed.jpeg&w=3840&q=75)
Transcribed Image Text:5. Erina observed that the borax she uses to clean the house is only partially soluble with
water. She found on the internet that borax is composed of sodium tetraborate
(Na,B,0;(OH), • 8H,0) and wanted to analyze its solubility. The dissolution of borax is:
Na,B,0;(OH), • 8H20(9 = 2 Na (aq) + B40;(OH), (aq) + 8 H20o
A 50.0 mL saturated solution was prepared for the experiment. After filtering the solution,
a 5.00 mL aliquot was transferred to a 25.0 mL Erlenmeyer flask and was titrated using
pre-standardized 0.4320 M HCI. The endpoint was reached after the addition of 4.73 mL
titrant.
Since the tetraborate anion (B,0;(OH),?) is a weak base, the tetraborate ion reacts with
HCI by the reaction:
B,0,(OH), (aq) + 2 H*(aq) + 3 H,0g = 4 H;BO3(aq)
a. Write the K, expression for the dissolution process.
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