3.) A 15.00 mL sample of 0.250M formic acid (HCOOH, Ka - 1.8 x 104) is titrated with 0.300 M sodium hydroxide (NaOH). The following neutralization reaction is observed. Calculate the pH of the solution at the following intervals of NaOH added. HCOOH(aq) + NAOH(aq) → NaCOOH(aq) + H2O(1) a.) 4.50 mL NaOH b.) Half-equivalence point c.) 12.5 mL NaOH

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A: pH - It is the negative logarithm of the hydrogen ion concentration of a solution.  Given:- Ka =…

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A: pH of the weak acid for the reaction H2A <==> HA- ......(Ka1) HA- <==> A2- ........(Ka2)…

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A: pH is the power of a substance that how much acidic or alkaline that substance is.

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Q: (i) Define pH in words. The strong acid HClaq has a pH value of 1, use the following equation for a…

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Q: The pH of an aqueous solution of 0.291 M ammonium perchlorate, NH4ClO4 (aq), is This solution is -5…

A: Concentration of NH4ClO4 = 0.291 MKb of NH3 = 1.80×10-5

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A:

Q: 1) Calculate the pH of a solution prepared by dissolving 2.35 g of sodium acetate, CH,COONa, in 81.5…

A:

Q: Propionic acid, HC3H5O2, has Ka= 1.34 x 10–5. (a) What is the molar concentration of H3O+ in 0.15 M…

A: HC3H5O2 is a weak acid and dissociates in aqueous solution as: HC3H5O2+H2O↔C3H5O2-+H3O+

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A:

Q: Calculate the change in pH when 7.00 mL of 0.100 M HCl(aq) is added to 100.0 mL of a buffer solution…

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Q: The major component of vinegar is acetic acid, CH3COOH. Its Ka is 1.8 × 10-5 . One student used…

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Q: Calculate the change in pH when 4.00 mL of 0.100 M HCl(aq) is added to 100.0 mL of a buffer solution…

A:

Q: For the reaction of hydrazine (N2H4) in water, H,NNH, (ag) + H20(1) = H,NNH3* (aq) + OH (ag) K, is…

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Q: Calculate the pH of a solution by dissolving 1.90 g of sodium acetate, CH3COONa, in 71.0 mL of 0.15…

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Q: Calculate the change in pH when 6.00 mL of 0.100 M HCl(aq) is added to 100.0 mL of a buffer solution…

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Q: of 0.35 M HCl(aq)? (c) What is the volume of 0.35 M HCl (aq) req

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Q: Calculate the pH of 0.10 M (COOH)2 (aq), oxalic acid. Ka1 = 5.9 × 10–2 ; Ka2 = 6.4 × 10–5.

A: