The dissociation of molecular iodine into iodine atoms is represented as At 1000.0 K, the equilibrium constant K for the reaction is 3.80x 10 , Suppose you start with 0.0451 mol of L, in a 2.27 L flask at 1000.0 K, what are the 2. concentrations of the gases at equilibrium?
The dissociation of molecular iodine into iodine atoms is represented as At 1000.0 K, the equilibrium constant K for the reaction is 3.80x 10 , Suppose you start with 0.0451 mol of L, in a 2.27 L flask at 1000.0 K, what are the 2. concentrations of the gases at equilibrium?
Chemistry
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ISBN:9781305957404
Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
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Chapter1: Chemical Foundations
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Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...
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Transcribed Image Text:The dissociation of molecular iodine into iodine atoms is represented as
-D5
At 1000 0K, the equilibrium constant K for the reaction is 3.80× 10 °, Suppose you start with 0.0451 mol of L in a 2.27 L flask at 1000.0 K, What are the
concentrations of the gases at equilibrium?
Part 1 of 2
What is the equilibrium concentration of I,? Round your answer to 3 significant digits.
Part 2 of 2
What is the equilibrium concentration of 12 Round your answer to
significant digits.
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