### Hypothesis Testing for Smartphone Carrier's Data Speeds#### Problem StatementThe display provided from technology available below results from using data for a smartphone carrier's data speeds at airports to test the claim that they are from a population having a mean less than 4.00 Mbps. Conduct the hypothesis test using these results. Use a 0.05 significance level. Identify the null and alternative hypotheses, test statistic, P-value, and state the final conclusion that addresses the original claim.#### Null and Alternative HypothesesAssuming all conditions for conducting a hypothesis test are met, what are the null and alternative hypotheses?- **Option A:** - Null Hypothesis (H₀): μ ≥ 4.00 Mbps - Alternative Hypothesis (H₁): μ < 4.00 Mbps- **Option B:** - Null Hypothesis (H₀): μ = 4.00 Mbps - Alternative Hypothesis (H₁): μ < 4.00 Mbps- **Option C:** - Null Hypothesis (H₀): μ ≥ 4.00 Mbps - Alternative Hypothesis (H₁): μ ≠ 4.00 Mbps- **Option D:** - Null Hypothesis (H₀): μ = 4.00 Mbps - Alternative Hypothesis (H₁): μ ≠ 4.00 Mbps- **Option E:** - Null Hypothesis (H₀): μ = 4.00 Mbps - Alternative Hypothesis (H₁): μ > 4.00 Mbps#### Identifying Test Statistics- **Round to two decimal places as needed.**#### Identifying the P-Value- **Round to three decimal places as needed.**#### Final ConclusionState the final conclusion that addresses the original claim:H₀: **There is** [__fill in__] **evidence to support the claim that the sample is from a population with a mean less than 4.00 Mbps.**---In this problem, you would typically choose the correct null and alternative hypotheses and then perform statistical analysis to find the test statistic and the P-value. Based on the P-value compared to the significance level (0.05), you would draw a conclusion to either reject the null hypothesis or fail to reject it. If rejected, you would have evidence to support the ### T-Test Result Display from Technology#### Variables- **Population Mean (µ)**: Less than 4.00- **Test Statistic (t)**: -3.825604- **P-value (p)**: 0.000185- **Sample Mean (x̄)**: 3.38- **Sample Standard Deviation (Sx)**: 1.145979- **Sample Size (n)**: 50#### Explanation of Results- **Population Mean (µ)**: The hypothesis test evaluates whether the true population mean is less than 4.00.- **Test Statistic (t)**: The calculated t-value is -3.825604, which indicates how many standard deviations the sample mean is from the hypothesized population mean.- **P-value (p)**: With a p-value of 0.000185, which is less than the significance level (commonly 0.05), the result is statistically significant, leading us to reject the null hypothesis.- **Sample Mean (x̄)**: The average value of the sample data is 3.38.- **Sample Standard Deviation (Sx)**: The variability or dispersion of the sample data points around the sample mean is 1.145979.- **Sample Size (n)**: The number of observations or data points in the sample is 50.This data helps in conducting a T-Test to infer if there is enough statistical evidence to say that the population mean is less than 4.0 based on the given sample data.

Given data isMean(x)=3.38standard deviation(s)=1.145979sample size(n)=50significance level(α)=0.05

Answered: The display provided from technology…

MATLAB: An Introduction with Applications

6th Edition

ISBN:9781119256830

Author:Amos Gilat

Publisher:Amos Gilat

Chapter1: Starting With Matlab

Section: Chapter Questions

Problem 1P

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A data set includes data from 500 random tornadoes. The display from technology available below results from using the tornado lengths (miles) to test the claim that the mean tornado length is greater than 2.2 miles. Use a 0.05 significance level. Use the display to identify the null and alternative hypotheses, test statistic, and P-value. State the final conclusion that addresses the original claim.
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