Factinate.com claims that 84% of teenagers think highly of their mother. To investigate this claim, aschool psychologist selects a random sample of 150 teenagers and finds that 135 think highly oftheir mother. Do these data provide convincing evidence that the true proportion of teens who thinkhighly of their mother is greater than 0.84?1. State appropriate hypotheses for performing a significance test. Be sure to define the parameterof interest.The school psychologist performed the significance test and obtained a P-value of 0.0225.2. Explain what it would mean for the null hypothesis to be true in this setting.3. Interpret the P-value.4. What conclusion would you make at the a = 0.05 level?

Given that, Population proportion (p) = 0.84 Sample size (n) = 150 No. of teenagers think highly of…

Answered: 1. State appropriate hypotheses for…

MATLAB: An Introduction with Applications

6th Edition

ISBN:9781119256830

Author:Amos Gilat

Publisher:Amos Gilat

Chapter1: Starting With Matlab

Section: Chapter Questions

Problem 1P

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Solve the problem. 9) The table shows the number of households burglarized in a sample of households with dogs and in a sample of households without dogs. Assume that you plan to use a significance level of a = 0.01 to test the claim that p1 < p2. Find the critical value(s) for this hypothesis test. Do the data support the claim that a smaller proportion of households with pet dogs are burglarized? 9) Household with Dog Household without Dog Number of households in sample Number of households burglarized 206 140 20 11 A) z = -2.575; no B) z = -2.33; no C) z = 2.33; yes D) z = -1.96; yes
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A poll of 2,122 randomly selected adults showed that 93% of them own cell phones. The technology display below results from a test of the claim that 92% of adults own cell phones. Use the normal distribution as an approximation to the binomial distribution, and assume a 0.05 significance level to complete parts (a) through (e). Test of p = 0.92 vs p *0.92 Sample X 1 N 2,122 1970 Sample p 0.928369 95% CI The P-value is (Round to three decimal places as needed.) (0.917397,0.939341) a. Is the test two-tailed, left-tailed, or right-tailed? O Two-tailed test O Left-tailed test O Right tailed test b. What is the test statistic? The test statistic is (Round to two decimal places as needed.) c. What is the P-value? Z-Value 1.42 P-Value 0.155
A change is made that should improve student satisfaction with the parking situation at your school. Before the change, 37% of students approve of the parking that's provided. The null hypothesis Ho : p = 0.37 is tested against the alternative H.: p > 0.37 The given hypotheses are incorrect. What are the appropriate hypotheses for performing this significance test? Ho : p = 0.37; Ha :p> 0.37, where p= the true proportion of students that approve of the parking that's provided. Ho : p = 0.37; Ho : p + 0.37, where p= the true proportion of students that approve of the parking that's provided. Ho : p > 0.37; Họ : p = 0.37, where p= the true proportion of students that approve of the parking that's provided. Ho : p = 0.37; H, : p + 0.37, where p the sample proportion of students that approve of the parking that's provided. Ho : p > 0.37; Họ : p = 0.37, where p the sample proportion of students that approve of the parking that's provided.
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A simple random sample of size n= 16 is drawn from a population that is normally distributed. The sample mean is found to be x= 21.2 and the sample standard deviation is found to be s= 6.5. Determine if the population mean is different from 26 at the a= 0.05 level of significance. Complete parts (a) through (d) below. Click here to view the standard normal distribution table (page 1). Click here to view the standard normal distribution table (page 2). Click here to view the table of criticaltevalmes (a) Determine the null and alternative hypotheses. Ho H,: (Type integers or decimals. Do not round.) (b) Identify the test statistic. (Round to two decimal places as needed.) Approximate the P-value. The P-value is in the range (c) State the conclusion for the test.
K The display provided from technology available below results from using data for a smartphone carrier's data speeds at airports to test the claim that they are from a population having a mean less than 5.00 Mbps. Conduct the hypothesis test using these results. Use a 0.05 significance level. Identify the null and alternative hypotheses, test statistic, P-value, and state the final conclusion that addresses the original claim. Click the icon to view the display from technology. D iew an example Get more help. 42 W S Assuming all conditions for conducting a hypothesis test are met, what are the null and alternative hypotheses? OA. Ho: 5.00 Mbps J D. Ho: -5.00 Mbps H₁: - Clear all : - ; X option F11 { [ ? + = 1 I Check answer F12 } ] delete retu
Q30
[13] How does p-value relate to null hypothesis? a. Reference for making decisions about the null hypothesis b. Illustrates how bad the null hypothesis was crafted c. Provides a scale to check the validity of the null hypothesis d. All of the above
Imagine that you found that participants in the jelly bean condition had an average acne score o and your significance level was .041. Because your signifinace level is lEss than .05 you reject the null hypothesis. Result #2 imagine that you found that the participants in the jelly bean condition had an average acne score of and your significance level was .00. Because your significance level is less than .05 you reject the null hypothesis. You also note that this result suggest a bigger effect size(30verus10 on your dependant variable). What is the ma in difference between the two scenarios?
.2.3 Assigned Media The P-value for a hypothesis test is shown. Use the P-value to decide whether to reject Ho when the level of significance is (a) a = 0.01, (b) a = 0.05, and (c) a= 0.10. P=0.0618 (a) Do you reject or fail to reject Ho at the 0.01 level of significance? A. Reject Ho because the P-value, 0.0618, is greater than a= 0.01. B. Reject Ho because the P-value, 0.0618, is less than a =0.01. C. Fail to reject Ho because the P-value, 0.0618, is less than oa= 0.01. O D. Fail to reject Ho because the P-value, 0.0618, is greater than a= 0.01. Click to select your answer and then click Check Answer. parts Type here to search 0 耳 PrtScn Home End F1 F2 F3 F4 F5 F6 F7 F8 F9 %23

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