A data set includes data from 500 random tornadoes. The display from technology available below results from using the tornado lengths (miles) to test the claim that the mean tornado length is greater than 2.2 miles. Use a 0.05 significance level. Use the display to identify the null and alternative hypotheses, test statistic, and P-value. State the final conclusion that addresses the original claim.

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A data set includes data from 500 random tornadoes. The display from technology available below results from using the tornado lengths (miles) to test the claim that the mean tornado length is greater than 2.2 miles. Use a 0.05 significance level. Use the display to identify the null and alternative hypotheses, test statistic, and P-value.

State the final conclusion that addresses the original claim.

### Hypothesis Test Results

**μ**: Mean of variable

- **Null Hypothesis (H₀)**: μ = 2.2
- **Alternative Hypothesis (H₁)**: μ > 2.2

#### Test Summary for Variable: Length

| Variable | Sample Mean | Std. Err. | DF  | T-Stat  | P-value |
|----------|--------------|-----------|-----|---------|---------|
| Length   | 2.38563      | 0.251663  | 499 | 0.737613| 0.2305  |

**Explanation of the Table:**

1. **Variable**: The attribute being tested, which in this case is "Length".
2. **Sample Mean**: The average value of the sample, which is 2.38563.
3. **Standard Error (Std. Err.)**: The standard deviation of the sample mean, which is 0.251663.
4. **Degrees of Freedom (DF)**: The number of independent values or quantities which can be assigned to a statistical distribution, which is 499.
5. **T-Statistic (T-Stat)**: The test statistic value for the hypothesis test, calculated to be 0.737613.
6. **P-value**: The probability of observing the test results under the null hypothesis, which is 0.2305 in this case.

**Conclusion:**
Given the P-value (0.2305) is greater than a common significance level (e.g., 0.05), we do not have enough evidence to reject the null hypothesis. Therefore, we cannot conclude that the mean length is greater than 2.2.
Transcribed Image Text:### Hypothesis Test Results **μ**: Mean of variable - **Null Hypothesis (H₀)**: μ = 2.2 - **Alternative Hypothesis (H₁)**: μ > 2.2 #### Test Summary for Variable: Length | Variable | Sample Mean | Std. Err. | DF | T-Stat | P-value | |----------|--------------|-----------|-----|---------|---------| | Length | 2.38563 | 0.251663 | 499 | 0.737613| 0.2305 | **Explanation of the Table:** 1. **Variable**: The attribute being tested, which in this case is "Length". 2. **Sample Mean**: The average value of the sample, which is 2.38563. 3. **Standard Error (Std. Err.)**: The standard deviation of the sample mean, which is 0.251663. 4. **Degrees of Freedom (DF)**: The number of independent values or quantities which can be assigned to a statistical distribution, which is 499. 5. **T-Statistic (T-Stat)**: The test statistic value for the hypothesis test, calculated to be 0.737613. 6. **P-value**: The probability of observing the test results under the null hypothesis, which is 0.2305 in this case. **Conclusion:** Given the P-value (0.2305) is greater than a common significance level (e.g., 0.05), we do not have enough evidence to reject the null hypothesis. Therefore, we cannot conclude that the mean length is greater than 2.2.
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