A data set includes weights (in grams) of 33 Reese's Peanut Butter Cup Miniatures. The accompanying Statdisk display shows results from using all 33 weights to test the claim that the sample isfrom a population with a mean equal to 8.953 g. Test the given claim by using the display provided from Statdisk. Use a 0.05 significance level.Click the icon to view the Statdisk display.Identify the null and alternative hypotheses.Ho HH₁ H #=8.9538.953Statdisk Display(Type integers or decimals. Do not round.)Identify the test statistic.(Round to two decimal places as needed.)t TestTest Statistic, t:Critical t:P-value:-3.40633± 2.036930.00179- X

Claim: The sample is from a population with a mean equal to 8.953 g. Based on the claim, the null…

Answered: A data set includes weights (in grams)…

MATLAB: An Introduction with Applications

6th Edition

ISBN:9781119256830

Author:Amos Gilat

Publisher:Amos Gilat

Chapter1: Starting With Matlab

Section: Chapter Questions

Problem 1P

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Perform the following hypothesis test of a proportion: HO: p = 0.125 HA: p 0.125 The sample proportion is 0.1 based on a sample size of 95. Use a 10% significance level. What is the p-value?
A study analyzed the sustainability behaviors of CPA corporations. The level of support for corporate sustainability (measured on a quantitative scale ranging from 0 to 160 points) was obtained for each in a sample of 974 senior managers at CPA firms. The CEO of a CPA firm claims that the true mean level of support for sustainability is 71. Complete parts a through e below. i Click the icon to view a printout of the analysis. a. Specify the null and alternative hypotheses for testing this claim. O A. Ho: μ=71 Ha: μ#71 O C. Ho: μ#71 H₂: H=71 O B. Ho: μ = 71 Ha: μ>71 O D. Ho: μ = 71 Ha: μ<71
Kenneth, a competitor in cup stacking, claims that his average stacking time is 8.2 seconds. During a practice session, Kenneth has a sample stacking time mean of 7.8 seconds based on 11 trials. At the 4% significance level, does the data provide sufficient evidence to conclude that Kenneth's mean stacking time is less than 8.2 seconds? Accept or reject the hypothesis given the sample data below. H0:μ=8.2 seconds; Ha:μ<8.2 seconds α=0.04 (significance level) z0=−1.75 p=0.0401 Select the correct answer below: a. Do not reject the null hypothesis because the p-value 0.0401 is greater than the significance level α=0.04. b. Reject the null hypothesis because the p-value 0.0401 is greater than the significance level α=0.04. c. Reject the null hypothesis because the value of z is negative. d. Reject the null hypothesis because |−1.75|>0.04. e. Do not reject the null hypothesis because |−1.75|>0.04.
The coach of a very popular men’s basketball team claims that the average distance the fans travel to the campus to watch a game is 35 miles. The team members feel otherwise. A sample of 16 fans who travel to games was randomly selected and yielded a mean of M= 36 miles and s= 5 miles. Test the coach’s claim at the 5% (.05) level of significance. one-tailed or two-tailed test: State the hypotheses: df= tα or t value for the critical region = sM = t (test statistic)= Decision:
What is the null and alternative hypothesis for the following problem? Thank you
= Rhino viruses typically cause common colds. In a test of the effectiveness of echinacea, 43 of the 49 subjects treated with echinacea developed rhinovirus infections. In a placebo group, 92 of the 109 subjects developed rhinovirus infections. Use a 0.05 significance level to test the claim that echinacea has an effect on rhinovirus infections. Complete parts (a) through (c) below. a. Test the claim using a hypothesis test. Consider the first sample to be the sample of subjects treated with echinacea and the second sample to be the sample of subjects treated with a placebo. What are the null and alternative hypotheses for the hypothesis test? OA. Ho: P₁ P2 H₁: P₁ = P2 O D. Ho: P₁ P2 H₁: P₁ P2 Identify the test statistic. Z= (Round to two decimal places as needed.) Identify the P-value. OB. Ho: P₁ P2 H₁: P₁ P2 ? O E. Ho: P₁ P2 H₁: P₁ P2 P-value= (Round to three decimal places as needed.) What is the conclusion based on the hypothesis test? The P-value is the significance level of a =…
Portland State University (PSU) reported that 64% of their students receive financial aid. A PSU administrator feels that their school may have a different proportion compared to all of Oregon schools. A random sample of 409 students in Oregon found that 259 receive financial aid. Test the claim that proportion of students that receive financial aid in Oregon is different than PSU. Use a 1% significance level. Give answer to at least 4 decimal places. a. What are the correct hypotheses? (Select the correct symbols and use decimal values not percentages.) Ho: Select an answer ?v H₁: Select an answer ? ✓ Based on the hypotheses, compute the following: b. Test Statistic = c. p-value = d. Based on the above we choose to Select an answer e. The correct summary would be: Select an answer that the proportion of students that receive financial aid in Oregon is different than the PSU reported value of 64%.
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The US Department of Energy reported that 45% of homes were heated by natural gas. A random sample of 348 homes in Oregon found that 156 were heated by natural gas. Test the claim that proportion of homes in Oregon that were heated by natural gas is different than what was reported. Use a 1% significance level. Give answer to at least 4 decimal places. What are the correct hypotheses? (Select the correct symbols and use decimal values not percentages.) Ho: P Test Statistic = =✓ ✓ OF H₁: P Based on the hypotheses, compute the following: p-value = 45 0° 45 OB vo
If you use a 0.025 level of significance in a (two-tail) hypothesis test, what is your decision rule for rejecting a null hypothesis that the population mean is 600 if you use the Z test? Click here to view page 1 of the Normal table. LOADING... Click here to view page 2 of the Normal table. LOADING... Question content area bottom Part 1 Which of the following decision rules is correct? A. Reject H0 if ZSTAT<−2.24 or ZSTAT>+2.24. B. Reject H0 if −2.24<ZSTAT<+2.24. C. Reject H0 if −1.96<ZSTAT<+1.96. D. Reject H0 if ZSTAT<−1.96 or ZSTAT>+1.96.
Does stress affect the recall ability of police witnesses? This issue was studied in an experiment that tested eyewitness memory a week after a nonstressful interrogation of a cooperative suspect and a stressful interrogation [the way of questioning] of an uncooperative suspect. The numbers of details recalled a week after the incident are summarized in the margin (based on data from "Eyewitness Memory of Police Trainees for Realistic Role Plays," by Yuille et al., Journal of Applied Psychology, Vol. 79, No. 6). Use 0.01 level of significance to test the daim in the artidle that stress decreased the amount recalled. Assume equal population variances. Nonstress Stress n = 40 X= 53.3 n2 = 40 = 45.3 S, = 13,2 S = 11.6 a. Claim (in symbolic form): Ho: На: b. level of significance: test-statistic: tail of distribution: c. Decision Rule: Reject Ho if d. Computation e. Decision (Reject Ho or Failed to reject Ho) f. Conclusion
Researchers reported a study in which 409 domestic violence defendants were randomly assigned to counseling and probation (the experimental group) or just probation (the control group). Out of people 238 in the counseling group, 51 were arrested within 12 months. Out of 171 people assigned to probation,41 were arrested within 12 months. Determine whether counseling lowered the arrestrate; use a 0.05 significance level. Start by comparing the percentages. 1. Write the hypothesis for the test. Ho ___ Ha ____ 2. z = ___ (Round to two decimal places asneeded.) 3. p-value = ____ (Round to three decimal places asneeded.) 4. What is the conclusion for this test? Use a significance level of 0.05.

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