A data set includes weights (in grams) of 33 Reese's Peanut Butter Cup Miniatures. The accompanying Statdisk display shows results from using all 33 weights to test the claim that the sample isfrom a population with a mean equal to 8.953 g. Test the given claim by using the display provided from Statdisk. Use a 0.05 significance level.Click the icon to view the Statdisk display.Identify the null and alternative hypotheses.HoH₁:(Type integers or decimals. Do not round.)Statdisk Displayt TestTest Statistic, t:Critical t:P-value:- 3.40633± 2.036930.00179х

Answered: A data set includes weights (in grams)…

MATLAB: An Introduction with Applications

6th Edition

ISBN:9781119256830

Author:Amos Gilat

Publisher:Amos Gilat

Chapter1: Starting With Matlab

Section: Chapter Questions

Problem 1P

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The Bureau of Labor Statistics reports that the official unemployment rate for Black people was 10.4% and 4.7% for White people in February 2015. Select all correct answers for this question. O The samples of white and black people are independent. The explanatory variable is the unemployment rate. The response variable is the unemployment rate. The response variable is race.
Perform the following hypothesis test of a proportion: HO: p = 0.125 HA: p 0.125 The sample proportion is 0.1 based on a sample size of 95. Use a 10% significance level. What is the p-value?
A study analyzed the sustainability behaviors of CPA corporations. The level of support for corporate sustainability (measured on a quantitative scale ranging from 0 to 160 points) was obtained for each in a sample of 974 senior managers at CPA firms. The CEO of a CPA firm claims that the true mean level of support for sustainability is 71. Complete parts a through e below. i Click the icon to view a printout of the analysis. a. Specify the null and alternative hypotheses for testing this claim. O A. Ho: μ=71 Ha: μ#71 O C. Ho: μ#71 H₂: H=71 O B. Ho: μ = 71 Ha: μ>71 O D. Ho: μ = 71 Ha: μ<71
Kenneth, a competitor in cup stacking, claims that his average stacking time is 8.2 seconds. During a practice session, Kenneth has a sample stacking time mean of 7.8 seconds based on 11 trials. At the 4% significance level, does the data provide sufficient evidence to conclude that Kenneth's mean stacking time is less than 8.2 seconds? Accept or reject the hypothesis given the sample data below. H0:μ=8.2 seconds; Ha:μ<8.2 seconds α=0.04 (significance level) z0=−1.75 p=0.0401 Select the correct answer below: a. Do not reject the null hypothesis because the p-value 0.0401 is greater than the significance level α=0.04. b. Reject the null hypothesis because the p-value 0.0401 is greater than the significance level α=0.04. c. Reject the null hypothesis because the value of z is negative. d. Reject the null hypothesis because |−1.75|>0.04. e. Do not reject the null hypothesis because |−1.75|>0.04.
The coach of a very popular men’s basketball team claims that the average distance the fans travel to the campus to watch a game is 35 miles. The team members feel otherwise. A sample of 16 fans who travel to games was randomly selected and yielded a mean of M= 36 miles and s= 5 miles. Test the coach’s claim at the 5% (.05) level of significance. one-tailed or two-tailed test: State the hypotheses: df= tα or t value for the critical region = sM = t (test statistic)= Decision:
What is the null and alternative hypothesis for the following problem? Thank you
= Rhino viruses typically cause common colds. In a test of the effectiveness of echinacea, 43 of the 49 subjects treated with echinacea developed rhinovirus infections. In a placebo group, 92 of the 109 subjects developed rhinovirus infections. Use a 0.05 significance level to test the claim that echinacea has an effect on rhinovirus infections. Complete parts (a) through (c) below. a. Test the claim using a hypothesis test. Consider the first sample to be the sample of subjects treated with echinacea and the second sample to be the sample of subjects treated with a placebo. What are the null and alternative hypotheses for the hypothesis test? OA. Ho: P₁ P2 H₁: P₁ = P2 O D. Ho: P₁ P2 H₁: P₁ P2 Identify the test statistic. Z= (Round to two decimal places as needed.) Identify the P-value. OB. Ho: P₁ P2 H₁: P₁ P2 ? O E. Ho: P₁ P2 H₁: P₁ P2 P-value= (Round to three decimal places as needed.) What is the conclusion based on the hypothesis test? The P-value is the significance level of a =…
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If you use a 0.025 level of significance in a (two-tail) hypothesis test, what is your decision rule for rejecting a null hypothesis that the population mean is 600 if you use the Z test? Click here to view page 1 of the Normal table. LOADING... Click here to view page 2 of the Normal table. LOADING... Question content area bottom Part 1 Which of the following decision rules is correct? A. Reject H0 if ZSTAT<−2.24 or ZSTAT>+2.24. B. Reject H0 if −2.24<ZSTAT<+2.24. C. Reject H0 if −1.96<ZSTAT<+1.96. D. Reject H0 if ZSTAT<−1.96 or ZSTAT>+1.96.

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