Cadmium, a heavy metal, is toxic to animals. Mushrooms, however, are able to absorb and accumulate cadmium at high concentrations. Somegovernments have a safety limit for cadmium in dry vegetables at 2.3 parts per million (ppm). A hypothesis test is to be performed to decide whether themean cadmium level in a certain mushroom is not equal to the government's recommended limit. Complete parts (a) through (c) below.a. Determine the null hypothesis.HoiHppm(Type an integer or a decimal. Do not round.)b. Determine the alternative hypothesis.Ha: Hppm(Type an integer or a decimal. Do not round.)c. Classify the hypothesis test as two tailed, left tailed, or right tailed.The hypothesis test is

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Answered: Cadmium, a heavy metal, is toxic to…

MATLAB: An Introduction with Applications

6th Edition

ISBN:9781119256830

Author:Amos Gilat

Publisher:Amos Gilat

Chapter1: Starting With Matlab

Section: Chapter Questions

Problem 1P

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3.4.2 2. Find the following z-scores: a. Za10 b. Zo975 c. Z,005 0.15 e. Z30 "0.80 f. Z 0.30
An airline is considering charging a two-tiered rate for checked bags based on their weight. Before deciding at what weight to increase the rate, the airline wishes to estimate the mean weight per bag checked by passengers. It wants the estimate to be within ±0.25 pounds of the true population mean. A pilot sample of checked bags produced the results shown below. data: 4938384233323437404440364340393649444438 a. What sample size should the airline use if it wants to have 95% confidence? b Suppose the airline managers do not want to take as large a sample as the one determined in part a. What general options do they have to lower the required sample size? The sample size must be at least ???. (Round up to the nearest whole number.) b. What could the managers do to lower the required sample size? Select all that apply. A. Increase the margin of error B. Use a larger pilot sample C. Reduce the level of confidence D.…
(3-B is needed to answer it I am only asking for question 4.) 3) You go out and collect the following estimates of earthworms / acre:54,276 57,378 51,108 66,190 66,232 59,018 57,159These data yield the following: ̄y = 59,765.86, and s = 5,689.606a) Construct a 90% CI for these data.b) Construct a 99% CI for these data.c) Darwin once estimated that an acre of soil had about 50,000 worms in it. Is his estimateconsistent with the data above? (Historical note: His estimate was considered way too high inhis day). 4) Consider the results of 3(b). Notice that all the data fit within the 99% confidence interval. Is thisusually the case (in other words, will a 99% CI contain most of the observations)?Caution: a lot of people get this wrong! Here's a hint: suppose you had measured the worms in6000 acres (instead of just 7). What happens to the confidence interval? If you're not sure,substitute 6,000 for 7 in your calculation for (b) to see what happens.
To determine if their 14 oz filling machine is properly adjusted, Harvey Soft Drinks has decided to use an X-Chart which uses the range to estimate the variability in the sample. J. Answer How to enter your answ Table Step 1 of 7: What is the Center Line of the control chart? Round your answer to three decimal places. Control Chart Period 1 2 3 4 5 6 7 8 9 10 11 Select the Copy Table button to copy all values. To select an entire row or column, either click on the row or column header or use the Shift and arrow keys. To find the average of the selected cells, select the Average Values button. Copy Table Average Values The average of the selected cell(s) is 14.000. Copy Value Sample Mean Sample Range 14.0060 0.04 0.04 0.04 0.10 0.08 0.09 0.07 0.05 0.05 0.06 0.07 obs1 obs2 obs3 obs4 obs5 14.00 13.99 14.03 14.01 14.00 14.02 14.05 14.05 14.01 14.04 14.0340 14.02 14.01 14.05 14.04 14.02 14.0280 14.04 13.97 14.05 13.95 14.00 14.0020 13.96 14.01 14.00 14.04 14.02 14.0060 13.96 14.00 14.00…
A process is monitored for defective items by taking a sample of 200 items each day and calculating the proportion that are defective. Let p; be the proportion of defective items in the ith sample. For the last 30 samples, the sum of the proportions is E P; = 1.64. Calculate the center line and the 30 upper and lower control limits for a p chart.
Listed below are the measured radiation absorption rates ( in 5 - number summary . W/kg) corresponding to 11 cell phones . Use the given data to construct a boxplot and identify the 1.49,1.25, 1.38, 1.04, 1.46, 1.31, 1.28, 0.73, 1.41, 0.58, 1.36
b?
A drug company claims that their products’ contaminations never vary by more than 2%. Sample of 5 specimens were tested and the percentages of the purities are recorded as Observation no. 1 2 3 4 5 Percentages (%) 98.8 97.2 98.9 97.7 97.9 a. Do the sample data have enough proof to oppose the manufacturer's claim? (HINT: take the range of 2% equal 4o.) b. Find a 90% confidence interval for o?.
The data found below measure the amounts of greenhouse gas emissions from three types of vehicles. The measurements are in tons per year, expressed as CO2 equivalents. Use a 0.025 significance level to test the claim that the different types of vehicle have the same mean amount of greenhouse gas emissions. Based on the results, does the type of vehicle appear to affect the amount of greenhouse gas emissions? Click the icon to view the data. What are the hypotheses for this test? O A. Ho: At least one of the means is different from the others. H₁ H₁ H₂ H3 OB. Ho: H₁ H₁: H1 H₂ =H3 H₂ H3 OC. Ho: H₁ H₂ H3 H₁: At least one of the means is different from the others. O D. Ho: H₁ H₂ H3 H₁: H₁ H₂ =H3 Data Table Type A 6.2 6.2 6.5 7.4 7.1 6.1 6.9 7.3 6.9 6.7 Print C Type B 7.7 7.5 8.7 8.1 8.6 8.8 8.4 8.5 Type C 8.5 9.3 9.6 9.1 9.1 9.1 9.8 9.5 9.9 Done O X
The data found below measure the amounts of greenhouse gas emissions from three types of vehicles. The measurements are in tons per year, expressed as CO2 equivalents. Use a 0.05 significance level to test the claim that the different types of vehicle have the same mean amount of greenhouse gas emissions. Based on the results, does the type of vehicle appear to affect the amount of greenhouse gas emissions? Click the icon to view the data. What are the hypotheses for this test? OA. Ho: H₁ H₂ H3 H₁: H₁ H₂ H3 OB. Ho: H₁ H₂ =H3 H₁: At least one of the means is different from the others. O C. Ho: At least one of the means is different from the others. H₁: H₁=H₂ =H3 OD. Ho: H₁ H₂ H3 H₁: H1₁ H₂ H3 Determine the test statistic. F = (Round to two decimal places as needed.) Identify the P-value. P-value= (Round to two decimal places as needed.) What is the conclusion of the test? the null hypothesis. Conclude that the type of vehicle Data Table C Type A 6.5 6.2 6.5 6.5 5.8 7.5 6.4 6.4 6.2 6.9…
Rhino viruses typically cause common colds. In a test of the effectiveness of echinacea, 33 of the 38 subjects treated with echinacea developed rhinovirus infections. In a placebo group, 94 of the 111 subjects developed rhinovirus infections. Use a 0.01 significance level to test the claim that echinacea has an effect on rhinovirus infections. Complete parts (a) through (c) below. a. Test the claim using a hypothesis test. Consider the first sample to be the sample of subjects treated with echinacea and the second sample to be the sample of subjects treated with a placebo. What are the null and alternative hypotheses for the hypothesis test? O A. Ho: P1 #P2 Hy:P1 =P2 O B. Ho: P1 =P2 H1: P1 P2 H1: P1 #P2 Identify the test statistic. (Round to two decimal places as needed.) Identify the P-value. P-value = (Round to three decimal places as needed.) What is the conclusion based on the hypothesis test? the null hypothesis. There sufficient evidence to support the claim that echinacea…
Refer to the figure at the right. At a= 0.10, can you reject the claim that the proportion of 18 to 24-year-olds living in their parents' homes in 2000 was the same for men and women? Assume the survey included a random sample of 270 men and 278 women. Percentage of 18- to 24-year olds living in parents' homes 70, 60.4% 45% 54.6% 50.3% 2000 2012 Men Women Identify the null and alternative hypotheses. Choose the correct answer below. O B. Ho: P, * P2 Ha: P1 = P2 OD. Ho: P1 > P2 YA. Ho: P1 = P2 H3: P, * P2 OC. Ho: P, P2 Ha: P, SP2 Find the critical value(s). The critical value(s) is(are). (Round to two decimal places as needed. Use a comma to separate answers as needed.)

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