tures. The accompanying Statdisk displ Using all 35 weights to test the claim that the sample is from a population with a mean equal to 8.953 g. Test the given claim by using the display provided from Statdisk. Use a 0.10 significance level. Click the icon to view the Statdisk display. Identify the null and alternative hypotheses. Ho: μ = 8.953 H₁: μ # 8.953 (Type integers or decimals. Do not round.) Identify the test statistic. -3.66 (Round to two decimal places as needed.) Identify the P-value. (Round to three decimal places as needed.) ...
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- Use technology to help you test the claim about the population mean, µ, at the given level of significance, a, using the given sample statistics. Assume the population is normally distributed. Claim: µs 1210; a = 0.07; o=201.42. Sample statistics: x = 1231.33, n= 300 Identify the null and alternative hypotheses. Choose the correct answer below. O A. Ho: µs 1210 H3: µ> 1210 O B. Ho: µs 1231.33 Ha p> 1231.33 O D. H μ2 1210 O C. Ho: µ> 1231.33 Ha: us 1231.33 H3: µ 1210 Click to select your answer and then click Check Answer.Kenneth, a competitor in cup stacking, claims that his average stacking time is 8.2 seconds. During a practice session, Kenneth has a sample stacking time mean of 7.8 seconds based on 11 trials. At the 4% significance level, does the data provide sufficient evidence to conclude that Kenneth's mean stacking time is less than 8.2 seconds? Accept or reject the hypothesis given the sample data below. H0:μ=8.2 seconds; Ha:μ<8.2 seconds α=0.04 (significance level) z0=−1.75 p=0.0401 Select the correct answer below: a. Do not reject the null hypothesis because the p-value 0.0401 is greater than the significance level α=0.04. b. Reject the null hypothesis because the p-value 0.0401 is greater than the significance level α=0.04. c. Reject the null hypothesis because the value of z is negative. d. Reject the null hypothesis because |−1.75|>0.04. e. Do not reject the null hypothesis because |−1.75|>0.04.The coach of a very popular men’s basketball team claims that the average distance the fans travel to the campus to watch a game is 35 miles. The team members feel otherwise. A sample of 16 fans who travel to games was randomly selected and yielded a mean of M= 36 miles and s= 5 miles. Test the coach’s claim at the 5% (.05) level of significance. one-tailed or two-tailed test: State the hypotheses: df= tα or t value for the critical region = sM = t (test statistic)= Decision:
- The data in the accompanying table give the weights (in g) of randomly selected quarters that were minted after 1964. The quarters are supposed to have a median weight of 5.670 g. Use the sign test and a 0.01 significance level to test the claim that the median is equal to 5.670 g. Do quarters appear to be minted according to specifications? Click the icon to view the data. What are the null and alternative hypotheses? O A. Ho: Median weight = 5.670 g H₁: Median weight 5.670 g More Info OB. Ho: Median weight ≤ 5.670 g H₁: Median weight = 5.670 g O D. Ho: Median weight = 5.670 g H₁: Median weight # 5.670 g 0 Post-1964 Quarters 5.5863 5.5764 5.6582 5.5649 5.5844 5.7402 5.7367 5.6057 5.5995 5.6165 5.6448 5.5974 5.6609 5.6363 5.6352 5.5986 5.5797 5.5501 5.6238 5.6462 5.6423 5.7021 5.5481 5.7078 5.6055 5.5324 5.7417 5.6776 5.5924 5.5691 5.5666 5.7287 5.6312 5.6017 5.6626 5.6436 5.6634 5.6132 5.5441 5.6363 -A study was done using a treatment group and a placebo group. The results are shown in the table. Assume that the two samples are independent simple random H samples selected from normally distributed populations, and do not assume that the population standard deviations are equal. Complete parts (a) and (b) below. Use a 0.01 significance level for both parts. a. Test the claim that the two samples are from populations with the same mean. What are the null and alternative hypotheses? OA. Ho: #₁ = 1₂ H₁: H₁ H₂ OC. Ho: H₁A study was done using a treatment group and a placebo group. The results are shown in the table. Assume that the two samples are independent simple random samples selected from normally distributed populations, and do not assume that the population standard deviations are equal. Complete parts (a) and (b) below. Use a 0.10 significance level for both parts. a. Test the claim that the two samples are from populations with the same mean. What are the null and alternative hypotheses? OA. Ho: H₁ H₂ H₁: Hq ZH₂ OC. Ho: H₁ H₂ H₁: Hy > H₂ The test statistic, t, is. (Round to two decimal places as needed.) (Round to three decimal places as needed.) The P-value is State the conclusion for the test. C... OB. Ho: H₁ H₂ H₁: Hy #H₂ OD. Ho: Hg #U2 H₁: HyChoose the appropriate statistical test. When computing, be sure to round each answer as indicated. A dentist wonders if depression affects ratings of tooth pain. In the general population, using a scale of 1-10 with higher values indicating more pain, the average pain rating for patients with toothaches is 6.8. A sample of 30 patients that show high levels of depression have an average pain rating of 7.1 (variance 0.8). What should the dentist determine? 1. Calculate the estimated standard error. (round to 3 decimals). [st.error] 2. What is thet-obtained? (round to 3 decimals). 3. What is the t-cv? (exact value) 4. What is your conclusion? Only type "Reject" or Retain"Use the following R output to answer the question. Use the following R output to answer the question. >chisq.test(data) Pearsons Chi-square test data:data X-squared=4.7194, df=2, p-value=0.09445 If the significance level is 5%, what conclusion can you make? Group of answer choices A. fail to reject the alternative hypothesis B. cannot determine C. fail to reject the null hypothesis D. reject the null hypothesis and accept the alternative hypothesisA study was done using a treatment group and a placebo group. The results are shown in the table. Assume that the two samples are independent simple random samples selected from normally distributed populations, and do not assume that the population standard deviations are equal. Complete parts (a) and (b) below. Use a 0.01 significance level for both parts. a. Test the claim that the two samples are from populations with the same mean. What are the null and alternative hypotheses? OA. Ho: H₁ H₂ H₁: H₁ H₂ OC. Ho: H₁ H¹/₂ H₁: H₁Use technology to help you test the claim about the population mean, μ, at the given level of significance, α, using the given sample statistics. Assume the population is normally distributed. Claim: μ>1290; α=0.02; σ=210.88. Sample statistics: x=1309.93, n=200 Identify the null and alternative hypotheses. Choose the correct answer below. A. H0: μ>1290 Ha: μ≤1290 B. H0: μ≥1290 Ha: μ<1290 C. H0: μ≤1290 Ha: μ>1290 D. H0: μ≥1309.93 Ha: μ<1309.93 E. H0: μ≤1309.93 Ha: μ>1309.93 F. H0: μ>1309.93 Ha: μ≤1309.93 Calculate the standardized test statistic. The standardized test statistic is nothing. (Round to two decimal places as needed.) Determine the P-value. P=nothing (Round to three decimal places as needed.) Determine the outcome and conclusion of the test. ▼ Reject Fail to reject H0. At the 2% significance level, there ▼ is not is enough…Test the claim below about the mean of the differences for a population of paired data at the level of significance a. Assume the samples are random and dependent, and the populations are normally distributed. Claim: 0 = 0 E. Ho: Hd 0 Ha: Hd s0 The test statistic is t= 1.43 . (Round to two decimal places as needed.) The critical value(s) is(are) to = (Round to two decimal places as needed. Use a comma to separate answers as needed.)Use a t-test to test the claim about the population mean u at the given level of significance a using the given sample statistics. Assume the population is normally distributed. Claim: u = 52,400; a 0.05 Sample statistics: x = 53,625, s 2700, n 20 %3D Click the icon to view the t-distribution table. What are the null and alternative hypotheses? Choose the correct answer below. O A. Ho H= 52,400 H3i H#52,400 O B. Ho: µz 52,400 Ha =52,400 O C. Ho H252,400 Ha H 52,400 Click to select your answer and then click Check Answer. 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