Consider a sample of 54 football games, where 30 of them were won by the home team. Use a 0.10 significance level to test the claim that the probability that the home team wins is greaterthan one-half.Identify the null and alternative hypotheses for this test. Choose the correct answer below.OA. Ho: p=0.5H₁: p<0.5B. Ho: p=0.5H₁: p>0.5OC. Ho: p>0.5H₁: p=0.5OD. Ho: p=0.5H₁: p 0.5Identify the test statistic for this hypothesis test.The test statistic for this hypothesis test is 0.82.(Round to two decimal places as needed.)Identify the P-value for this hypothesis test.The P-value for this hypothesis test is ☐(Round to three decimal places as needed.)

To address the problem, we need to set up the hypotheses and perform the necessary statistical…

Answered: Consider a sample of 54 football games,…

MATLAB: An Introduction with Applications

6th Edition

ISBN:9781119256830

Author:Amos Gilat

Publisher:Amos Gilat

Chapter1: Starting With Matlab

Section: Chapter Questions

Problem 1P

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All Test the claim about the population mean, p, at the given level of significance using the given sample statistics. age Claim: u = 50; a=0.02; o= 3.06. Sample statistics: x= 49.8, n 75 Identify the null and alternative hypotheses. Choose the correct answer below. gat O A. H, p 50 O C. H,: H> 50 Ha: u= 50 O D. Ho: H#50 Ha p= 50 OF Ho H=50 Ha:p< 50 E. H, H= 50 H3 u#50 Calculate the standardized test statistic. The standardized test statistic is -0.57. (Round to two decimal places as needed.) Determine the critical value(s). Select the correct choice below and fill in the answer box to complete your choice. (Round to two decimal places as needed.) O A. The critical value is. O B. The critical values are +
a. What are the null and alternative hypotheses? b. determine the test statistic c. determine the p-value
Assume that a simple random sample has been selected and test the given claim. Listed below are the lead concentrations in μg/g measured in different traditional medicines. Use a 0.05 significance level to test the claim that the mean lead concentration for all such medicines is less than 14 μg/g. 3.5 7.0 6.0 5.5 20.0 8.0 12.0 21.5 11.0 17.0 Identify the null and alternative hypotheses for this test. A. H0: μ=14 μg/g H1: μ<14 μg/g B. H0: μ<14 μg/g H1: μ=14 μg/g C. H0: μ=14 μg/g H1: μ>14 μg/g D. H0: μ=14 μg/g H1: μ≠14 μg/g Click to select your answer and then click Check Answer.
A news article that you read stated that. 51% of voters prefer the Democratic candidate. You think that the actual percent is different. 124 of the 213 voters that you surveyed said that they prefer the Democratic candidate. What can be concluded at the 0.05 level of significance? a. For this study, we should use Select an answer b. The null and alternative hypotheses would be: Ho:? Select an answer (please enter a decimal) ? Select an answer (Please enter a decimal) ces C. The test statistic ? ▼ (please show your answer to 3 decimal places.) d. The p-value - (Please show your answer to 4 decimal places.) e. The p-value is ? a f. Based on this, we should Select an answer the null hypothesis. g. Thus, the final conclusion is that ... The data suggest the population proportion is not significantly different 51% ata = 0.05, so there is sufficient evidence to conclude that the proportion of voters who prefer the Democratic candidate is equal to 51%. The data suggest the population…
A news article that you read stated that 51% of voters prefer the Democratic candidate. You think that the actual percent is smaller. 122 of the 248 voters that you surveyed said that they prefer the Democratic candidate. What can be concluded at the 0.01 level of significance? a. For this study, we should use Select an answer b. The null and alternative hypotheses would be: Ho: ? ✓ Select an answer H₁: ? Select an answer (please enter a decimal) (Please enter a decimal) c. The test statistic ? d. The p-value = e. The p-value is ? ✓ a f. Based on this, we should Select an answer the null hypothesis. (please show your answer to 3 decimal places.) (Please show your answer to 4 decimal places.)
2
Imagine you're a researcher and you need to perform a one-sided test of an alternate hypothesis. You decide to conduct a significance test at the .05 level. Which of the following of ranges of z-scores would make the test statistic significant at .05 (one -tail) but not at .01 . A. z < 1.96 B. 1.645 < z < 1.70 C. z > 1.60 D. - 1.96 < z < 1.96 E 1.645 < z < 2.33
Consider testing the hypotheses Ho: p 0.4 versus Hai p> 0.4. Four possible sample statistics, along with four possible p-values, are given. Match the statistics to their p-values. p= 0.42 p=0.38 p= 0.51 p= 0.46 D
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Test the claim about the population mean, u, at the given level of significance using the given sample statistics. Claim: u= 40; a = 0.06; o = 3.41. Sample statistics: x = 39.9, n = 71 Identify the null and alternative hypotheses. Choose the correct answer below. O A. Ho: H>40 О В. Но: н- 40 Hai H= 40 Ha: H 40 Ο F. Ho: μ# 40 Ha:H= 40
Big fish: A sample of 250 flounder of a certain species have sample mean weight 50.5 grams. Scientists want to perform a hypothesis test to determine how strong the evidence is that the mean weight is less than 49 grams. State the appropriate null and alternate hypotheses.
The mean price of mid-sized cars in a region is $57,600. A test is conducted to see if the claim is true. Identify the null hypothesis. ? v? v Identify the alternative hypothesis. ? v:?v| ? v Identify the type I error. O You decide that the mean price of mid-sized cars is not $57,600, when the mean price of mid- sized cars actually is $57,600. O You decide that the mean price of mid-sized cars is $57,600, when the mean price of mid- sized cars actually is not $57,600. O You decide that the mean price of mid-sized cars is not $57,600, when the mean price of mid- sized cars actually is nor $57,600. O You decide that the mean price of mid-sized cars is $57,600, when the mean price of mid- sized cars actually is $57,600. Identify the type II error. O You decide that the mean price of mid-sized cars is not $57,600, when the mean price of mid- sized cars actually is $57,600. O You decide that the mean price of mid-sized cars is $57,600, when the mean price of mid- sized cars actually is not…

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