The disk is rotating horizontally, and the block has a weight of 2 lb. Friction between the block and the slot is negligibly small, and the block is at rest with respect to the disk while it is traveling with a constant speed of 12 ft/sec. If the spring has a stiffness of 2.5 lb/ft and an undeformed length of 1.25 ft, calculate the force that the spring exerts on the block. Present your answer in lb using 3 significant figures. CEEEEEED k=2.5 lb/ft

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The disk is rotating horizontally, and the block has
a weight of 2 lb. Friction between the block and the
slot is negligibly small, and the block is at rest with
respect to the disk while it is traveling with a
constant speed of 12 ft/sec. If the spring has a
stiffness of 2.5 lb/ft and an undeformed length of
1.25 ft, calculate the force that the spring exerts on
the block. Present your answer in lb using 3
significant figures.
k= 2.5 lb/ft
Transcribed Image Text:The disk is rotating horizontally, and the block has a weight of 2 lb. Friction between the block and the slot is negligibly small, and the block is at rest with respect to the disk while it is traveling with a constant speed of 12 ft/sec. If the spring has a stiffness of 2.5 lb/ft and an undeformed length of 1.25 ft, calculate the force that the spring exerts on the block. Present your answer in lb using 3 significant figures. k= 2.5 lb/ft
Expert Solution
Step 1

The block is at rest means that there is no net force acting on the block. 

Hence, the centrifugal force exerting on the block is balanced by the pull of the spring. 

The outward force on the block due to rotation is 

F=mv2r

where r is the radius and v is the speed. m is the mass of the block. 

It is given that 

m=2 lbr=?v=12 ft/s

The restoring force by the spring is 

F=k(r-r0)k=spring constant=2.5 lb/ftr0=undeformed length= 1.25 ft

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