A force of 720 newtons stretches a spring 4 meters. A mass of 45 kilograms is attached to the end of the spring and is initially released from the equilibrium position with an upward velocity of 6 m/s. Find the equation of motion.\[ x(t) = -6 \cdot \sin(2t) \, \text{m} \]

Force applied F= 720 N Spring stretched = 4m Mass attached m= 45kg Velocity v= 6m/s

Answered: A force of 720 newtons stretches a…

Physics for Scientists and Engineers: Foundations and Connections

1st Edition

ISBN:9781133939146

Author:Katz, Debora M.

Publisher:Katz, Debora M.

Chapter16: Oscillations

Section: Chapter Questions

Problem 28PQ: We do not need the analogy in Equation 16.30 to write expressions for the translational displacement...

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A force of 720 newtons stretches a spring 4 meters. A mass of 45 kilograms is attached to the end of the spring and is initially released from the equilibrium position with an upward velocity of 6 m/s. Find the equation of motion. x(t) =-6- sin(21) x m