The diode current is 1.38 mA when the applied voltage is 180 mV, and 34 mA when the applied voltage is 415 mV. Detemmine n. Assume (KT/q) 23 mV.

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A: The solution can be achieved as follows.

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Q: can you please explain how this solved just the last step?

A: EVEN RECTANGULAR PULSE:

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Q: Can you help give a detailed step by step explanation of the math in this solution:

A: V2,n​=(1/1.9612∠−78.8∘)[(0.3603∠−146.3∘/V2,n−1​)−(1.9612∠101.3∘)(1∠0∘)]The process described in the…

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BJT (Bipolar Junction Transistor)

A BJT is a semiconductor device with 3 terminals that consist of a p-n junction diode that can amplify the signal or current. It is a current-controlled device. The three BJT terminals are base, collector, and emitter. The BJT works with the charge carrier, the two type of carriers in the BJT are holes and electrons, the charge carriers flow by the process of recombination. The signal to be amplifier is generally given as the input at the base terminal and an amplified form of it is available at the collector terminal.