The detailed results of a standard compaction test are shown in the table below. Determine the maximum dry unit weight and optimum water content. 1 Diameter of mold = 101.4 mm Height of mold = 116.7 mm Mass of mold, M = 4196.50 grams Unit weight data Water content data Mass of wet soil Mass of can and Mass of can (grams) M. Mass of can and and mold (grams) Mwm wet soil (grams) dry soil (grams) M. 5906.00 114.92 111.48 46.50 6056.00 163.12 155.08 46.43 6124.00 190.43 178.64 46.20 6156.00 193.13 178.24 46.50 6103.00 188.77 171.58 46.10

Q: The laboratory test results of standard proctor test are given in the tabl kimum dry unit weight of…

A: γwet=γbulk=wt of soilvolume of soilγdry=γd=wt of soil(1+moisture content)

Q: Following the sieve analysis and the specific gravity of "SAND 1", a hydrometer test was performed…

A: The hydrometer test is used to determine the distribution of soil particle sizes that are smaller…

Q: Plot the Standard Proctor curve of dry unit weight versus water content (see below table) and; a)…

A: Plot the compaction curve by keeping water content along the horizontal axis and the dry unit weight…

Q: Draw the compaction curve using the following given data from a standard Proctor test. 2. From…

A: Objective: To draw the compaction curve for the given Standard Proctor Test results, and determine…

Q: Consider the grain size gradation curve for the soil shown in the image below and classify the soil…

A: Look at the % passing through sieve no 200=20<50%⇒COARSE GRAINED SOIL

Q: A laboratory test was conducted according to Method A of the ASTM D4318 to find the liquid limit of…

A: The wet mass of the soil sample with the mass of the can is measured, again the dry mass of the…

Q: A column analysis of a flocculating suspension is shown below. The initial solids concentration is…

A: C0 = Intital solids concentration = 200 mg/L(a) Calculate the removal fraction at each depth and…

Q: Question 9 Soil placed on a can has been weighed before and after an oven-drying procedure. The…

A:

Q: TABLE 2 RESULTS OF ORI TEST Water Content (%) Weight (Kg) 14 1.45 16.5 1.71 18.5 1.87 20 1.88 21…

A:

Q: Standard Proctor test was conducted on a silty clay soil collected from a proposed construction…

A:

Q: What is dry unit weight of the soil sample below (va) in Ib/ft ? The combined weight of a mold and…

A: Given data : Combined weight of mold and compacted soil sample (W1)=8.7 lbMold weight (W2)=5 lbmolds…

Q: A Standard Proctor Test was completed according to Method A described in Chapter 12. The following…

A:

Q: The laboratory test data for a standard Proctor test are given below. Volume of Moisture content…

A:

Q: Question 4 (1 Listen The laboratory compaction tests requires several iterations of the test to be…

A:

Q: The results given in Table 1 were obtained in a particle size distribution test for soil sample…

A: The weight retained of soil is,To find: The gradation curve and its properties.

Q: a) Plot the grain size curve b) Calculate the coefficient of uniformity and the coefficient of…

A: For the given data, the particle size distribution curve is plotted below: a.

Q: A sample of soil obtained from a test pit 2 ft3 in volume has a weight of 210 lb. The entire sample…

A: Volume= 2 ft3 Total weight = 210lb Dry weight =185 lb

Soil Compaction Test

Soil compaction is the major area of geotechnical engineering. Soil is composed of multiple pores present on its surface, while the soil is mainly composed of gravel, sand, rocks, etc. The arrangement of these rocks and gravels is such that they build up voids (spaces) between them, which allows spaces for the roots of the plants and crops to spread and absorb the required amount of nutrients. Soil compaction is a major problem primarily caused by human activities, micro-organisms, and other multiple factors.