The decomposition reaction on N2O5 in carbon tetrachloride is 2 N2 O5-----> 4NO2 + O2. The rate law is first order in N2O5. At 64 °C the rate constant is 4.82 X 10-3s-1 (a) write the rate law for the reaction.  (b) what is the rate when the concentration of N2O5  is doubled from 0.0240 M to 0.0480 M?   Group of answer choices A) (a) rate= k[N2O5] (b) the rate doubles to 1.16 x 10E(-4) M/sec   B.) (a) rate= k[N2O5] (b) the rate is halved to 5.8 x 10E(-5) M/sec   C.) (a) rate= k[N2O5] (b) the rate doubles to 2.32 x 10E(-4) M/sec   D.) (a) rate= k[N2O5]0 (b) the rate stays the same

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