a) The reaction of NO2 has been studied as a function of temperature. For the following decomposition reactions, the rate constant is 2.7 × 10-2M-1s-1 at 227 °C and 2.4 x 10-1M-1s-1 at 305 °C. 9. 2 NO2 → 2 NO + 02 Calculate the activation energy for this reaction. 9. b) Nitrogen oxide converts ozone into molecular oxygen as follows: 03 + NO → 02 + NO2 k[03][NO]. Show which of the following The experimental rate law is: Rate = mechanism/mechanisms are consistent with the experimental rate law. Mechanism 1: 03 + NO → 02 + NO3 (slow) 0 + 03 → 2 02 (fast) NO3 + NO → 2 NO2 (fast) Mechanism 2: 03 = 02 + 0 (fast) NO + 0 → N02 (slow) Mechanism 3: 03 + NO → 02 + NO2 (slow)
a) The reaction of NO2 has been studied as a function of temperature. For the following decomposition reactions, the rate constant is 2.7 × 10-2M-1s-1 at 227 °C and 2.4 x 10-1M-1s-1 at 305 °C. 9. 2 NO2 → 2 NO + 02 Calculate the activation energy for this reaction. 9. b) Nitrogen oxide converts ozone into molecular oxygen as follows: 03 + NO → 02 + NO2 k[03][NO]. Show which of the following The experimental rate law is: Rate = mechanism/mechanisms are consistent with the experimental rate law. Mechanism 1: 03 + NO → 02 + NO3 (slow) 0 + 03 → 2 02 (fast) NO3 + NO → 2 NO2 (fast) Mechanism 2: 03 = 02 + 0 (fast) NO + 0 → N02 (slow) Mechanism 3: 03 + NO → 02 + NO2 (slow)
Chemistry
10th Edition
ISBN:9781305957404
Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Chapter1: Chemical Foundations
Section: Chapter Questions
Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...
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Question
![a) The reaction of NO2 has been studied as a function of temperature. For the following decomposition
reactions, the rate constant is 2.7 × 10-2M-'s-1 at 227 °C and 2.4 x 10-1M-1s-1 at 305 °C.
9.
2 NO2 → 2 N0 + 02
Calculate the activation energy for this reaction.
9.
b) Nitrogen oxide converts ozone into molecular oxygen as follows:
Оз + NO -> 02 + NO2
The experimental rate law is: Rate = k[03][NO]. Show which of the following
mechanism/mechanisms are consistent with the experimental rate law.
Mechanism 1:
03 + NO → 02 + NO3
(slow)
0 + 03 → 2 02
(fast)
NO3 + NO → 2 NO2
(fast)
Mechanism 2:
032 02 + 0
(fast)
NO +0 → N02
(slow)
Mechanism 3:
03 + NO → 02 + NO2
(slow)](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2Fd02c1c30-3760-46b0-b707-1872e0b8abab%2Fabf6c39e-27f1-4e6a-a9a6-51c4f639fbd8%2F9w8nxcm_processed.png&w=3840&q=75)
Transcribed Image Text:a) The reaction of NO2 has been studied as a function of temperature. For the following decomposition
reactions, the rate constant is 2.7 × 10-2M-'s-1 at 227 °C and 2.4 x 10-1M-1s-1 at 305 °C.
9.
2 NO2 → 2 N0 + 02
Calculate the activation energy for this reaction.
9.
b) Nitrogen oxide converts ozone into molecular oxygen as follows:
Оз + NO -> 02 + NO2
The experimental rate law is: Rate = k[03][NO]. Show which of the following
mechanism/mechanisms are consistent with the experimental rate law.
Mechanism 1:
03 + NO → 02 + NO3
(slow)
0 + 03 → 2 02
(fast)
NO3 + NO → 2 NO2
(fast)
Mechanism 2:
032 02 + 0
(fast)
NO +0 → N02
(slow)
Mechanism 3:
03 + NO → 02 + NO2
(slow)
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