The activation energy for a particular reaction is 102 kJ/mol. If the rate constant is 1.35 × 10⁻⁴ s⁻¹ at 318 K, what is the rate constant at 273 K?
The activation energy for a particular reaction is 102 kJ/mol. If the rate constant is 1.35 × 10⁻⁴ s⁻¹ at 318 K, what is the rate constant at 273 K?
Chemistry
10th Edition
ISBN:9781305957404
Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Chapter1: Chemical Foundations
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The activation energy for a particular reaction is 102 kJ/mol. If the rate constant is 1.35 × 10⁻⁴ s⁻¹ at 318 K, what is the rate constant at 273 K?
Expert Solution
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Step 1
Activation energy at two different temperature related with rate constants. The relationship is given by Arrhenius equation as -
log(k2/k1) = - Ea/2.303 R(1/T2-1/T1)
Here,
k1 = rate constant at 318 K = 1.35×10-4 s-1
k2 = rate constant at 273 K = ?
T1 = initial temperature = 318 K
T2 = final temperature = 273 K
R = gas constant = 8.314 J/mol K
Ea = activation energy = 102 kJ = 102000 J
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