This is the next part of the worksheet but I totally get if only the truth table may be solved. Thank you!For each of the 8 outputs in the truth-table, construct a K-Map to determine thesimplest Boolean expression. Be sure to look for XOR and XNOR simplifications toreduce you final gate count. For example: XY’Z + XYZ’ = X(Y xor Z). Since segments a-fof HEX1 will always be off, k-maps are necessary. the DE board utilizes common-anode seven-segment displays, thus; a 0 is placed in the truthtable anywhere a segment needs to be on, and a 1 anywhere a segment needs to be off.Note that the HEX1 display will only be blank or -, so its g segment is the only one that needs tobe in the truth table.W X Y Z Signed godecimal。。。。。0000100000111111O1111O1O1101 01111O1011 0 11 1 1001-1HEX Displaysfo eodo cogb0а 0 g1

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Answered: the DE board utilizes common-anode…

Introductory Circuit Analysis (13th Edition)

13th Edition

ISBN:9780133923605

Author:Robert L. Boylestad

Publisher:Robert L. Boylestad

Chapter1: Introduction

Section: Chapter Questions

Problem 1P: Visit your local library (at school or home) and describe the extent to which it provides literature...

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This is the next part of the worksheet but I totally get if only the truth table may be solved. Thank you!

For each of the 8 outputs in the truth-table, construct a K-Map to determine the
simplest Boolean expression. Be sure to look for XOR and XNOR simplifications to
reduce you final gate count. For example: XY’Z + XYZ’ = X(Y xor Z). Since segments a-f
of HEX1 will always be off, k-maps are necessary.

the DE board utilizes common-anode seven-segment displays, thus; a 0 is placed in the truth
table anywhere a segment needs to be on, and a 1 anywhere a segment needs to be off.
Note that the HEX1 display will only be blank or -, so its g segment is the only one that needs to
be in the truth table.
W X Y Z Signed go
decimal
。。。。。
0
0
0010
0
0
0
0
1
1
1
1
1
1
O
1
1
1
1
O
1
O
1
1
0
1 0
1
1
1
1
O
1
0
1
1 0 1
1 1 10
0
1
-1
HEX Displays
fo eo
do co
g
b0
а 0 g1

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