X, = B Therefore the X-OR gate using 2:1 MUX is implemented as -X, 2 -F 2:1 MUX 2:1 MUX
X, = B Therefore the X-OR gate using 2:1 MUX is implemented as -X, 2 -F 2:1 MUX 2:1 MUX
Introductory Circuit Analysis (13th Edition)
13th Edition
ISBN:9780133923605
Author:Robert L. Boylestad
Publisher:Robert L. Boylestad
Chapter1: Introduction
Section: Chapter Questions
Problem 1P: Visit your local library (at school or home) and describe the extent to which it provides literature...
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Question
Explain whats going on SIMPLY!
![ALLUTumg tu quesuoII.
The truth table of X-OR gate is given as
A.
B.
1.
For input 'Xo and X1 and select input 'S' the
expression of the output 'Y' of the
multiplexer is given as
F= SX, + SX1
Step 2
Now in order to make X-OR gate using 2:1
MUX,
S = A
Xo = B
X, = B
Therefore the X-OR gate using 2:1 MUX is
implemented as
X, 2
2:1 MUX
2:1 MUX
The output of MUX 1 gives B
And the output of MUX 2 gives
F=AB+ AB](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2Fc78e66a6-0428-4a28-bf85-72fa25c7e828%2Fde955353-8b43-49a1-9e1b-903c2bada179%2F9j1sf5_processed.jpeg&w=3840&q=75)
Transcribed Image Text:ALLUTumg tu quesuoII.
The truth table of X-OR gate is given as
A.
B.
1.
For input 'Xo and X1 and select input 'S' the
expression of the output 'Y' of the
multiplexer is given as
F= SX, + SX1
Step 2
Now in order to make X-OR gate using 2:1
MUX,
S = A
Xo = B
X, = B
Therefore the X-OR gate using 2:1 MUX is
implemented as
X, 2
2:1 MUX
2:1 MUX
The output of MUX 1 gives B
And the output of MUX 2 gives
F=AB+ AB
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