The data in the table below is for a closed-polygon traverse. Balance the traverses by coordinates using the compass rule. BC CD Course AB Bearing N8°17'02"E N87°02′05"E S14°47'06" W N68°43'20" W Length (ft) 403.73 653.16 550.84 622.63 DA Compute the unadjusted departures. Express your answers in feet to five significant figures and separated by commas. DEPAB- DеPBC DеPCD-DEPDA= Lat AB. Lat BC. LatCD. Lat DA = ΑΣΦΗ Π [ΠΙΑΣΦ Compute the unadjusted latitudes. Express your answers in feet to five significant figures and separated by commas + Compute the linear misclosure. Express your answer in feets to three significant figures. ΗΠΙΑΣΦΠΠvec It vec • Avec 3 O ? ft CE CE ? ? ft ft

The data in the table below is for a closed-polygon traverse. Balance the traverses by coordinates using the compass rule. BC CD Course AB Bearing N8°17'02"E N87°02′05"E S14°47'06" W N68°43'20" W Length (ft) 403.73 653.16 550.84 622.63 DA Compute the unadjusted departures. Express your answers in feet to five significant figures and separated by commas. DEPAB- DеPBC DеPCD-DEPDA= Lat AB. Lat BC. LatCD. Lat DA = ΑΣΦΗ Π [ΠΙΑΣΦ Compute the unadjusted latitudes. Express your answers in feet to five significant figures and separated by commas + Compute the linear misclosure. Express your answer in feets to three significant figures. ΗΠΙΑΣΦΠΠvec It vec • Avec 3 O ? ft CE CE ? ? ft ft

Structural Analysis

6th Edition

ISBN:9781337630931

Author:KASSIMALI, Aslam.

Publisher:KASSIMALI, Aslam.

Chapter2: Loads On Structures

Section: Chapter Questions

Problem 1P

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Consider a closed-polygon traverse (lengths in feet). Balance the traverses by coordinates using the compass rule. Course Bearing Length AB N 22°36'40" W 314.02 BC S 60°39'24" W 264.49 CD S 38°46'10" E 213.50 DA N 88° 22'58" E 217.69 Part A Compute the unbalanced departures. Express your answers, separated by commas, to three decimal places. AB=, BC =, CD=, DA = Submit ΠΑΣΦ ↓↑. vec Request Answer Review
10. TRANSIT RULE. Given in the accompanying tabulations are observed and calculated data for two different traverses. LATITUDE DEPARTURE AZIMUTH FROM SOUTH LINE DISTANCE +N -S +E 99°45' 154 00' 242 30' 353 15' AB 357.20 m 60.49 352.04 183. 18 164.64 80.30 CD 430.05 198.57 381.46 DA 425.18 422.23 49.97 Sums 1395.61m + 423. 70 -422.23 +431.43 -432,34 (D) (ENL) (ESL) (EED) (E WD)
1. Determine the distance between survey stations R and S, which are separated by a body of water. An EDM device is not available. A baseline RT is established and taped; the angles at the stations have been measured and adjusted. Compute the required distance RS using the given data. S R River 345.67 ft Baseline T 4 R-ST = 67° 11'39" 4 T-RS = 33°49'38"
Given the following tabulated data for a closed traverse in which the lengths of BC and CD have not been measured in the field. Determine these unknown quantities. LATITUDES DEPARTURES LINE LENGTH BEARING N E W AB 639.32 m N 09° 30' W BC UNKNOWN N 56° 55' W CD UNKNOWN S 56° 13' W DE 570.53 S02° 02' E EA 1,082.71 S89° 31'E SUMS
A closed traverse has the following data: LINE / LENGTH (m) / Bearing AB / 126.00 m / N 35° E BC / 233.00 m/ S 10° E CA / 170.00 m/ N 41° W 1. || Find the departure disclosure of the traverse. A. 1.201 m B. 2.423 m C. 1.006 m D. 2.321 m 2. Find the latitude disclosure. A. 1.267 m B. 1.889 m C. 2.054 m D. 1.560 m
1. Given the following tabulations are observed and calculated data for a traverse. Balance the latitudes and departures by the COMPASS RULE and compute for the area of the closed traverse by DOUBLE PARALLEL METHOD (DPD). Tip: Before you compute for the area of the closed traverse, you must first adjust the latitudes and departures. LINE DISTANCE AZIMUTH LATITUDES LATITUDES DEPARTURES DEPARTURES (-S) FROM SOUTH 99°45' 154°00' 242°30' 353°15' (+N) (+E) (-W) 357.20 m 183.18 430.05 AB 60.49 164.64 198.54 352.04 80.30 BC CD DA SUMS 381.46 49.97 425.18 422.23 423.70 422.23 431.43 432.34
Latitude and Departure Given the observed data of a closed traverse, determine the latitudes and departures of each line. Line Length Bearing AB 427.000 m N 59°33’ E BC 301.950 m S 39°18’ E CD 445.660 m S 06°35’ W DE 326.730 m N 17°48’W EA 434.500 m N 70°59’ W * Indicate the sign for latitude and departure * Note: EXPRESS YOUR ANSWER UPTO 3 DECIMAL PLACES.
Problem 1. Given in the tabulation below are notes for an open traverse. Determine the latitude and departure of each course and tabulate each computed values accordingly. COURSE AB BC CD DE EF FG DISTANCE 550.30 m 395.48 m 462.70 m 631.22 m 340.05 m 275.86 m BEARING N 28°10' E S 69°35' E S 27°50' E N 50°00' E S 27°05' E DUE EAST
Problem 6 For the given data of a close traverse, determine the missing distance of course CD and the bearing of course EF. Solve the AREA using DMD and sketch the traverse. DISTANCE LINES BEARING LATITUDE DEPARTURE DMD DOUBLE AREA (m) AB 78 5 78°11' E BC 49 5 45°26' E CD 5 34°05' w DE 115 N 32°18' W EF 65 FA 62 N 29°20' w Area
6. LATITUDES tabulations are the observed data pertaining to four diffe- rent traverses. CoOmpute and tabulate the latitudes and departures of each course. AND DEPARTURERS. Given in the accompanying AZIMUTH FROM SOUTH LINE LENGTH BEARING LINE DISTANCE NO0° 42'E S85 57'E so3* 04'w S52 51'w 242 30' 353 15' 99 45' 154 00 AB 732.72m JK 430.05 m BC 324.78 KL 425.18 CD 477.24 LM 357.20 DA 388.08 MJ 183.18 AZIMUTH COURSE LENGTH COURSE LENGTH BEARING FROM NORTH 228 20' 267 43' 352 01' 82 12' 131 48' N59 33'E S39 18'E so6*35'w NI7:48'w N70°59'w 1-2 161.46 m 1-2 427.00 m 301.95 180.49 2-3 3-4 2-3 171.83 3-4 445.66 4-5 229.70 326.73 434.50 4-5 5-1 130.55 5-1 7. ERROR OF CLOSURE. Given the following tabulated data for vevs