The data in the table below is for a closed-polygon traverse. Balance the traverses by coordinates using the compass rule.| Course | Bearing | Length (ft) ||--------|---------------|-------------|| AB | N8°17'02"E | 403.73 || BC | N87°02'05"E | 622.63 || CD | S14°47'06"W | 653.16 || DA | N68°43'20"W | 550.84 |### Part A**Compute the unadjusted departures.**Express your answers in feet to five significant figures and separated by commas.\[ \text{Dep}_{AB}, \text{Dep}_{BC}, \text{Dep}_{CD}, \text{Dep}_{DA} = \] Submit [ ] Request Answer### Part B**Compute the unadjusted latitudes.**Express your answers in feet to five significant figures and separated by commas.\[ \text{Lat}_{AB}, \text{Lat}_{BC}, \text{Lat}_{CD}, \text{Lat}_{DA} = \]Submit [ ] Request Answer The image contains a problem related to surveying, specifically for a closed-polygon traverse, which involves balancing the traverse by coordinates using the compass rule.**Table Data:**- **Course and Bearing:** - AB: N8°17'02"E - BC: N87°02'05"E - CD: S14°47'06"W - DA: N68°43'20"W- **Length (ft):** - AB: 403.73 - BC: 622.63 - CD: 653.16 - DA: 550.84**Part C:**- Task: Compute the linear misclosure. - Instruction: Express your answer in feet to three significant figures. - Input field provided.**Part D:**- Task: Compute the relative precision. - Instruction: Express your answer as an integer. - Input field provided.Each section has options to submit the answer or request an answer.

The data in the table below is for a closed-polygon traverse. Balance the traverses by coordinates using the compass rule. Course AB BC CD DA Bearing N8°17'02"E N87°02′05"E S14°47'06" W N68°43'20" W Length (ft) 653.16 403.73 622.63 550.84 Part A Compute the unadjusted departures. Express your answers in feet to five significant figures and separated by commas. DEPAB. DеPBC. DePCD. DePDA= Submit ▾ Part B Request Answer Lat AB. Lat BC, LatcD. Lat DA= ■ Submit Request Answer ΑΣΦΗ | | | vec Compute the unadjusted latitudes. Express your answers in feet to five significant figures and separated by commas. a 197| ΑΣΦ.41 | vec → C PWC ? ? ft ft

The data in the table below is for a closed-polygon traverse. Balance the traverses by coordinates using the compass rule. Course AB BC CD DA Bearing N8°17'02"E N87°02′05"E S14°47'06" W N68°43'20" W Length (ft) 653.16 403.73 622.63 550.84 Part A Compute the unadjusted departures. Express your answers in feet to five significant figures and separated by commas. DEPAB. DеPBC. DePCD. DePDA= Submit ▾ Part B Request Answer Lat AB. Lat BC, LatcD. Lat DA= ■ Submit Request Answer ΑΣΦΗ | | | vec Compute the unadjusted latitudes. Express your answers in feet to five significant figures and separated by commas. a 197| ΑΣΦ.41 | vec → C PWC ? ? ft ft

Structural Analysis

6th Edition

ISBN:9781337630931

Author:KASSIMALI, Aslam.

Publisher:KASSIMALI, Aslam.

Chapter2: Loads On Structures

Section: Chapter Questions

Problem 1P

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Q8) Calculate the adjusted coordinates of all stations in the following traverse given that the station Q is the origin (use the transit rule method). Line Bearing Length (m) QR RS ST TQ N62° 02′ 30″E N27° 35' 10"W S78° 41' 15"W S07° 58' 00″W 172.2 87.52 93.81 141.08
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1. Given the following tabulations are observed and calculated data for a traverse. Balance the latitudes and departures by the COMPASS RULE and compute for the area of the closed traverse by DOUBLE PARALLEL METHOD (DPD). Tip: Before you compute for the area of the closed traverse, you must first adjust the latitudes and departures. LINE DISTANCE AZIMUTH LATITUDES LATITUDES DEPARTURES DEPARTURES (-S) FROM SOUTH 99°45' 154°00' 242°30' 353°15' (+N) (+E) (-W) 357.20 m 183.18 430.05 AB 60.49 164.64 198.54 352.04 80.30 BC CD DA SUMS 381.46 49.97 425.18 422.23 423.70 422.23 431.43 432.34
Surveying
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A and B are two points located on each bank of a river and near abutments of a proposed bridge. To determine its distance, a baseline CD 180m long was established on one bank of the river and the transit was set up at stations C and D and the azimuth were taken as follows: Line Azimuth C-D 210°00'; C-A 260°00'; C-B 290°00'; D-A 301 °00'; D-B 315°00' a. Find the distance AD. b. Find the distance BD. c. Find the distance AB.
Latitude and Departure Given the observed data of a closed traverse, determine the latitudes and departures of each line. Line Length Azimuth from North AB 161.460 m 228°20’ BC 180.490 m 267°43’ CD 171.830 m 352°01’ DE 229.700 m 82°12’ EA 130.550 m 131°48’ * Indicate the sign for latitude and departure * Note: EXPRESS YOUR ANSWER UPTO 3 DECIMAL PLACES. (Please provide a proven solution. Be mindful about the decimal places. Kindly answer this accurately. Thank You so much)
Latitude & Departure Problem B For the traverse sketch shown below, complete the latitude and departure calculations, determine the error of closure and relative accuracy. Start at Point A and work counter – clockwise around the loop Course Bearing Distance Cos Sin Latitude Departure Then adjust the traverse using compass rule
2. Given the data below of a closed traverse, Balance the traverse using Transit Rule, Compute area by DMD and DPD COURSE DEPARTURE LATITUDE AB -50 +490 BC +600 +590 CD +790 -320 DA -1300 -700
O/A missing course in closed traverse of data is illustrated in the table. missing line DA is compute distance and bearing for this line ? course distance bearing AB 261.27 N 31 22 E BC 322.78 N 79 11 E CD 517.66 S 19 59 W DA ?