Problem 10.8Using the compass (Bowditch) rule, adjust the departures and latitudes ofthe traverse given in the table below. The coordinates of station A areX = 17200.00 ft and Y= 15500.00 ft.CourseABBCCDDEEALength Departures Latitudes202.74-127.565 -157.577283.87-240.113151.42481.592498.37128.224320.33-125.5294.722380.78-379.946-25.193Σ = 1686.09 0.0010.063Part ACalculate the x-coordinates for the other stations.Express your answers in feet to seven significant figures separated by commas.B, C, D, E =SubmitPart BΑΣΦRequest AnswerB, C, D, E =SubmitCalculate the y-coordinates for the other stations.Express your answers in feet to seven significant figures separated by commas.ΑΣΦvecRequest Answer図」?vecft?ft

Coordinates of station A are given as X= 17200 Ft, Y= 15500 Ft Error in Departure = 0.001 and in…

Using the compass (Bowditch) rule, adjust the departures and latitudes of the traverse given in the table below. The coordinates of station A are X = 17200.00 ft and Y = 15500.00 ft. Length 202.74 283.87 CD 498.37 DE 320.33 EA 380.78 Course AB BC Departures Latitudes -127.565 -157.577 151.42 -240.113 128.224 294.722 -25.193 0.063 481.592 -125.5 -379.946 | Σ = 1686.09 | 0.001 Part A Calculate the x-coordinates for the other stations. Express your answers in feet to seven significant figures separated by commas. B, C, D, E = Submit Part B 1971 ΑΣΦ [1] vec Request Answer B, C, D, E = Calculate the y-coordinates for the other stations. Express your answers in feet to seven significant figures separated by commas. 195| ΑΣΦ ? vec ft ? ft

Using the compass (Bowditch) rule, adjust the departures and latitudes of the traverse given in the table below. The coordinates of station A are X = 17200.00 ft and Y = 15500.00 ft. Length 202.74 283.87 CD 498.37 DE 320.33 EA 380.78 Course AB BC Departures Latitudes -127.565 -157.577 151.42 -240.113 128.224 294.722 -25.193 0.063 481.592 -125.5 -379.946 | Σ = 1686.09 | 0.001 Part A Calculate the x-coordinates for the other stations. Express your answers in feet to seven significant figures separated by commas. B, C, D, E = Submit Part B 1971 ΑΣΦ [1] vec Request Answer B, C, D, E = Calculate the y-coordinates for the other stations. Express your answers in feet to seven significant figures separated by commas. 195| ΑΣΦ ? vec ft ? ft

Structural Analysis

6th Edition

ISBN:9781337630931

Author:KASSIMALI, Aslam.

Publisher:KASSIMALI, Aslam.

Chapter2: Loads On Structures

Section: Chapter Questions

Problem 1P

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A traverse has the following survey notes. Using the compass rule, determine the adjusted latitude of CD. * Course Bearing Distance АВ N 53.450E 59.800 S 66.900 S 29.133 W 76.580 N 52.000 W 95.780 BC E 70.360 CD DA O -66.913 O -66.940 O -66.939 O -66.931
The data in the table below is for a closed-polygon traverse. Course Azimuth Length (m) Interior Angles Departures Latitudes AB 75°14'47" 519.474 A = 12°25'31" 502.34691 132.29066 BC 303°34'09" 456.615 B = 48°19'25" -380.46099 252.48107 CD 250°11'30" 433.926 C=126°37'24" -408.2521 -147.04419 DE 116°15'03" 427.608 D= 46°03'36" 383.50666 -189.13288 EA 242°49'19" 107.83 E 306°34'19" -95.928244 -49.253868 = ▼ Part A Compute the adjusted departures. Express your answers in meters to six significant figures separated by commas. AB, BC, CD, DE, EA = Submit Request Answer ▼ Part B AB, BC, CD, DE, EA = Compute the adjusted latitudes. Express your answers in meters to six significant figures separated by commas. Submit 15] ΑΣΦ ↓1 vec Request Answer P -- ΑΣΦ ↓↑ vec ? ? m m
Q3- Correct the following traverse and compute station coordinates: Length (m) station A (x=1000m,b=1000m) AB B C side A BC CA 400.32 300.48 500.23 Azimuth 180° 00'00" 89°55'05" 323° 4' 44"
From the field notes of a closed traverse shown below, adjust the traverse using transit rule. LINES BEARING DISTANCES AB DUE NORTH 400 M BC N 45-00 E 800 M CD S 60-00 E 700 M DE S 20-00 W 600 M EA S 86-59 W 966.34 M
10. TRANSIT RULE. Given in the accompanying tabulations are observed and calculated data for two different traverses. LATITUDE DEPARTURE AZIMUTH FROM SOUTH LINE DISTANCE +N -S +E 99°45' 154 00' 242 30' 353 15' AB 357.20 m 60.49 352.04 183. 18 164.64 80.30 CD 430.05 198.57 381.46 DA 425.18 422.23 49.97 Sums 1395.61m + 423. 70 -422.23 +431.43 -432,34 (D) (ENL) (ESL) (EED) (E WD)
A closed traverse has the following data: LINE / LENGTH (m) / Bearing AB / 126.00 m / N 35° E BC / 233.00 m/ S 10° E CA / 170.00 m/ N 41° W 1. || Find the departure disclosure of the traverse. A. 1.201 m B. 2.423 m C. 1.006 m D. 2.321 m 2. Find the latitude disclosure. A. 1.267 m B. 1.889 m C. 2.054 m D. 1.560 m
The data in the table below is for a closed-polygon traverse. Course Azimuth Length (m) Interior Angles Departures Latitudes AB 75°14'47" 519.474 A = 12°25'31" 502.34691 132.29066 BC 303°34'09" 456.615 B = 48°19'25" -380.46099 252.48107 CD 250°11'30" 433.926 C = 126°37'24" -408.2521 -147.04419 DE 116°15'03" 427.608 D = 46°03'36" 383.50666 -189.13288 EA 242°49'19" 107.83 E 306°34'19" -95.928244 -49.253868 Ay, By, Cy, Dy, Ey = Submit Request Answer Part E AC = Submit Find the length of line AC. Express your answer in meters to six significant figures. ▾ Part F N 195| ΑΣΦ | 41 Request Answer Submit Π| ΑΣΦ [ΨΕΙ ΑΣΦ | Find the bearing of line AC. Express your answer in degrees to four significant figures. Request Answer vec 11 vec vec wwww. ? ? O m E ?
5.) Points A, B and C form a fixed triangle in the field. A total station instrument occupies point C and is used to determine a distance of 1783.32 feet to point A (side CA), and 301.62 feet to point B (side CB). If the interior angle at point C is determined to be 121°02'15", what is the distance of side AB?
1. Given the following tabulations are observed and calculated data for a traverse. Balance the latitudes and departures by the COMPASS RULE and compute for the area of the closed traverse by DOUBLE PARALLEL METHOD (DPD). Tip: Before you compute for the area of the closed traverse, you must first adjust the latitudes and departures. LINE DISTANCE AZIMUTH LATITUDES LATITUDES DEPARTURES DEPARTURES (-S) FROM SOUTH 99°45' 154°00' 242°30' 353°15' (+N) (+E) (-W) 357.20 m 183.18 430.05 AB 60.49 164.64 198.54 352.04 80.30 BC CD DA SUMS 381.46 49.97 425.18 422.23 423.70 422.23 431.43 432.34
Problem 6 For the given data of a close traverse, determine the missing distance of course CD and the bearing of course EF. Solve the AREA using DMD and sketch the traverse. DISTANCE LINES BEARING LATITUDE DEPARTURE DMD DOUBLE AREA (m) AB 78 5 78°11' E BC 49 5 45°26' E CD 5 34°05' w DE 115 N 32°18' W EF 65 FA 62 N 29°20' w Area
1. From the field notes of a closed traverse show below, adjust the traverse. LINES BEARING DISTANCES AB Due North 401 ВС N 45° E 797 CD S 60° E 700 DE S 200 W 600 EA S 86° 59' W 966.34 a. Solve for the Latitude and Departure b. Solve for the Adjusted and Balanced Departure and Latitude using compass/transit rule (specify your choice) c. Solve for the Balanced Length and Bearing d. Using the adjusted departure and latitude, calculate the area of the traverses using DMD/DPD method. (Specify your choice)
Bearing Angle Traverse Given the tabulated measurement of a closed traverse with unknown length and bearing of line EA, determine the following: The Latitude and Departure of each Line. The Length of Line EA. The Bearing of Line EA. Plot the Traverse. Line Length Bearing AB 585.730 m S 47°10’ E BC 496.080 m N 65°38’ E CD 999.900 m S 79°52’ E DE 795.340 m N 55°25’ E EA Unknown Unknown Note: EXPRESS YOUR ANSWER UPTO 3 DECIMAL PLACES. Note: Please be accurate in providing solution. Thank you so much.